Answer:the probability that a pensioner catches a flu is 0.3 or 
Step-by-step explanation:
<u>Data:</u>
a) Pensioners who have had a flu jab = 
b) Pensioners who did not had a flu jab = 1 - = 
For the first pair of arrows: a is the probability of the upper arrow and b is the probability of the lower arrow.
<em>If pensioner have had a flu jab, the probability of catching flu is 
</em>
Data:
c) Catching flu =
d) Not catching flu = 1 - = 
The second pair of arrows on the top: Top arrow is c and bottom arrow is d
<em>If pensioner did not have a flu jab, the probability of catching flu is 
</em>
<u>Data:</u>
e) Catching flu =
f) Not catching flu = 1 - =
The second pair of arrows on the bottom: Top arrow is e and bottom arrow is f.
Q) Probability pensioner catches a flu
P(catches the flu given that he had the flu jab) + P(catches the flu given that he did not have the flu jab)
( x ) + ( x )
= 0.02 + 0.28
= 0.3
Therefore, the probability that a pensioner catches a flu is 0.3 or
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Answer:
25/30 and 28/30
Step-by-step explanation:
1. To find the least common denominator, you need to find the least common multiple of the two denominators which are 6 and 15. Prime factorization of these numbers gives:
6 = 2 x 3
15 = 5 x 3
A number that would evenly divide both 6 and 15 must contain 2 x 3 x 5 which is 30.
Thus 30 is the least common denominator.
2. Now we need to somehow change both fractions to make them have a denominator of 30. To do this we can multiply by fractions with same numerator and denominator since that would be like multiplying by 1.
So, 5/6 x 5/5 = 25/30
And 14/15 x 2/2 = 28/30
Find the greatest common factor of both numbers:
Factors for 150:
150: 1, 2, 5 , 6, 10, 15, 25, 30, 50, 75, 150
Factors for 270:
1, 2, 3, 5, 6 , 9, 10, 15, 18, 27, 30, 45, 54, 90, 135, 270
The largest number they both have in common is 30, so the largest tile could be 30 cm^2.
Answer:
a) 7.5/3=2.5
b) about 3 pieces can be cut.
Step-by-step explanation:
Answer:
A) 2x*2 +6x -3x - 9= 2x*2 +3x -9
B) 2yx*2 +2yx +2y +3x*2 +3x +3
C) 36x*2 y +48yx +3xy*2 + 4y*2
D) 2x*3 - 4x*2 y + 3x -6y
