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Illusion [34]
3 years ago
8

The vector parametric equation for the line through the points (−1,−4,2) and (−1,0,−3) is:_______

Mathematics
1 answer:
ollegr [7]3 years ago
5 0

Answer: x(t)=-1

y(t)=-4+4(t)

z(t)=2-5(t)

Step-by-step explanation:

To find: The vector parametric equations for the line through the points (−1,−4,2) and (−1,0,−3).

Let A (−1,−4,2) and B(−1,0,−3)

First we find direction vectors : \overrightarrow{AB}=

Now, the parametric equations of the line:

x(t)=-1+0(t)

y(t)=-4+4(t)

z(t)=2-5(t)

Hence, the vector parametric equations for the line through the points (−1,−4,2) and (−1,0,−3):

x(t)=-1

y(t)=-4+4(t)

z(t)=2-5(t)

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Answer:

v =  \frac{32\pi}{3}

or

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Step-by-step explanation:

Given

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v = \pi \int\limit^2_0 (16x^2 - 4x^3 - 4x^3 + x^4 - x^4)\ dx

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v = 8\pi [ \frac{2x^{2+1}}{2+1} - \frac{x^{3+1}}{3+1} ]|\limit^2_0

v = 8\pi [ \frac{2x^{3}}{3} - \frac{x^{4}}{4} ]|\limit^2_0

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v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ \frac{2*0^{3}}{3} - \frac{0^{4}}{4} ])

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v=\frac{32*22}{3*7}

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