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4 years ago

The vector parametric equation for the line through the points (−1,−4,2) and (−1,0,−3) is:_______

Mathematics

1 answer:

ollegr [7]4 years ago

5 0

Answer: $x(t)=-1$

$y(t)=-4+4(t)$

$z(t)=2-5(t)$

Step-by-step explanation:

To find: The vector parametric equations for the line through the points (−1,−4,2) and (−1,0,−3).

Let A (−1,−4,2) and B(−1,0,−3)

First we find direction vectors : $\overrightarrow{AB}=$

Now, the parametric equations of the line:

$x(t)=-1+0(t)$

$y(t)=-4+4(t)$

$z(t)=2-5(t)$

Hence, the vector parametric equations for the line through the points (−1,−4,2) and (−1,0,−3):

$x(t)=-1$

$y(t)=-4+4(t)$

$z(t)=2-5(t)$

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