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bixtya [17]
3 years ago
8

What is the imaginary part of 21 – 14i?

Mathematics
2 answers:
Delvig [45]3 years ago
7 0

Answer: 14i

Step-by-step explanation:

AlexFokin [52]3 years ago
3 0
The imaginary would be 14. I got that because the "i" is after the 14 and you can't solve it.
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Complete this pattern 3400000, 34000,______3.4,______
Ira Lisetskai [31]
Well the pattern is moving 2 decimal places to the left to make it smaller so it starts off with 3,400,000. 34,000. Then 340. 3.4 and then .034.
ANSWER: 1) 340 2) .034
3 0
3 years ago
The table shows the number of games a team won and lost last season. Wins and Losses Last Season Number of Games Wins 24 Losses
sergiy2304 [10]

Answer:

The table shows the number of games a team won and lost last season is explained below in details.

Step-by-step explanation:

"Greg is creating a simulation, using previous year’s wins and losses, to foretell the team's conclusion.

He has six tickets for the team’s matches. The device which is most suitable for application in a simulation that implements the data is Probability.

Probability is the ratio of the probability that an incident will take place. The more eminent is the probability of an incident, there are likewise outcomes that the game will happen.

4 0
2 years ago
Read 2 more answers
A. Y=-5/2x+2<br> B. Y=2/5x+2<br> C. Y=-2/5x+2<br> D. Y=5/2x+2
FrozenT [24]
Answer:
B. Y=2/5x+2

Explanation:
Y-intercept: (0,2)
Slope: 4-2. 2
——=
5-0. 5
Y=2/5+2
5 0
3 years ago
Read 2 more answers
Show the work please
Kay [80]

Answer:

1) (x + 3)(3x + 2)

2) x= +/-root6 - 1 by 5

Step-by-step explanation:

3x^2 + 11x + 6 = 0 (mid-term break)

using mid-term break

3x^2 + 9x + 2x + 6 = 0

factor out 3x from first pair and +2 from the second pair

3x(x + 3) + 2(x + 3)

factor out x+3

(x + 3)(3x + 2)

5x^2 + 2x = 1 (completing squares)

rearrange the equation

5x^2 + 2x - 1 = 0

divide both sides by 5 to cancel out the 5 of first term

5x^2/5 + 2x/5 - 1/5 = 0/5

x^2 + 2x/5 - 1/5 = 0

rearranging the equation to gain a+b=c form

x^2 + 2x/5 = 1/5

adding (1/5)^2 on both sides

x^2 + 2x/5 + (1/5)^2 = 1/5 + (1/5)^2

(x + 1/5)^2 = 1/5 + 1/25

(x + 1/5)^2 = 5 + 1 by 25

(x + 1/5)^2 = 6/25

taking square root on both sides

root(x + 1/5)^2 = +/- root(6/25)

x + 1/5 = +/- root6 /5

shifting 1/5 on the other side

x = +/- root6 /5 - 1/5

x = +/- root6 - 1 by 5

x = + root6 - 1 by 5 or x= - root6 - 1 by 5

4 0
3 years ago
Sixth grade
garri49 [273]

Answer:

11-C

Step-by-step explanation:

Cause 11-C

equels the same amount as the one on the top of 11-C

6 0
2 years ago
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