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Minchanka [31]
3 years ago
11

A car travels 255 miles in 3 3/4 ​ at a constant speed. How many miles is the car traveling per hour?

Mathematics
1 answer:
disa [49]3 years ago
4 0

Answer:

eighty thousand one hundred and seventy

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How would you solve this?? i need to understand the process to theses types of problems!!
Evgen [1.6K]

Answer:

  CD = 10√3

Step-by-step explanation:

First of all, you need to understand the terms. The <em>incenter</em> is the center of an inscribed circle. Such a circle is tangent to all three sides of the triangle at points B, D, and F. The distances BG, DG, and FG are each the radius of the circle.

The diagram shows FG = 22, so that is also the measure of DG. This gives you two of the three sides of right triangle CDG, so you know enough to apply the Pythagorean theorem.

  CG^2 = CD^2 + DG^2

  28^2 = CD^2 + 22^2

  300 = CD^2 . . . . . . . . subtract 22^2

  10√3 = CD . . . . . . . . . take the positive square root

The measure of CD is 10√3.

_____

The process is to understand the geometric relationships and what they mean regarding the algebraic relationships. Then you use the algebraic relationships to write equations that let you find the unknowns you seek.

8 0
3 years ago
Properties of exponents. the answer is 1/2^12 i need help with the work
Vikentia [17]

Step-by-step explanation:

Answer in attached image...

hope it helps

7 0
3 years ago
Read 2 more answers
Solve<br> 3-**<br> The solution is k=
kiruha [24]

Answer: K= 8/3 or 2 2/3

Step-by-step explanation:

7 0
3 years ago
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There are 527 pencils,646 erasers and 748 sharpeners. These are to be put in separate packets containing the same number of item
sp2606 [1]

Answer:

  • 31 pencils
  • 38 erasers
  • 44 sharpeners

Step-by-step explanation:

The number of packets is the greatest common divisor of the given numbers of pencils, erasers, and sharpeners.

It can be helpful to look at the differences between these numbers:

  748 -646 = 102

  646 -527 = 119

The difference of these differences is 17, suggesting that will be the number of packets possible.

  527 = 17 × 31

  646 = 17 × 38

  748 = 17 × 44

The numbers 31, 38, and 44 are relatively prime (31 is actually prime), so there can be no greater number of packets than 17.

There will be 31 pencils, 38 erasers, and 44 sharpeners in each of the 17 packets.

_____

We may have worked the wrong problem. The way it is worded, the <em>maximum</em> number of items in each packet will be 527 pencils, 646 erasers, and 748 sharpeners in one (1) packet. The <em>minimum</em> number of items in each packet will be the number that corresponds to the maximum number of packets. Since 17 is the maximum number of packets, each packet's contents are as described above.

17 is the only common factor of the given numbers, so will be the number of groups (plural) into which the items can be arranged.

6 0
3 years ago
Suppose the firm in this example considers a second product that has a unit profit of $5 and requires 2 hours of production time
user100 [1]

The question is incomplete, here is the complete question

Recall the production model from Section 1.3:

Max 10x

s.t. 5x ≤ 40

x ≥ 0

Suppose the firm in this example considers a second product that has a unit profit of $5 and requires 2 hours for each unit produced. Assume total production capacity remains 40 units. Use y as the number of units of product 2 produced. . Show the mathematical model when both products are considered simultaneously.

Answer:

Max Profit: 10x + 5y

5x + 2y ≤ 40

x ≥ 0, y ≥ 0

Explanation:

x= number of units of product 1 produced

y = number of units of product 2 produced

Since the first product, x, has a unit profit of $10 and Max1 is 10x

Second product, y, has a unit profit of $5, Max2 = 5y

The maximum profit when both products are considered simultaneously is 10x + 5y

Max Profit = 10x + 5y

Time required for each unit of x is 5hours

Therefore, time required for x units is 5x hours

Time required for each unit of y is 2hours  

Therefore, time required for y units is 2y hours

Time required for the simultaneous production of both products is 5x + 2y

Since production capacity remains 40 units, 5x+2y ≤40

NB: The values of x and y cannot be negative  

5 0
3 years ago
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