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aleksandrvk [35]
3 years ago
13

Solve 6x-4=2x+16 HELLLLPPPPPPP

Mathematics
2 answers:
Troyanec [42]3 years ago
6 0
X=5 that is the answer
____ [38]3 years ago
5 0

To solve 6x-4=2x+16 for x:

Subtract 2x from both sides.

4x-4=16

Add 4 to both sides.

4x=20

Divide both sides by 4.

x=5

Your answer should be 5 or x=5.

Hope this helps :)

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Answer:

(a) P (U and V) = 0.

(b) P (U|V) = 0.

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Step-by-step explanation:

Mutually exclusive events are those events that cannot occur at the same time. That is, if events A and B are mutually exclusive then,

                                         P (A\cap B) = 0

<u>Given</u>:

Events U and V are mutually exclusive.

P (U) = 0.27 and P (V) = 0.56

(a)

As events U and V are mutually exclusive, the probability of their intersection will be 0.

That is,

P(U\ and\ V) = P (U\cap V) = 0

Thus, the value of P (U and V) is 0.

(b)

The conditional probability of event B given A is:

P(B|A) =\frac{P(A\cap B)}{P(B)}

Compute the value of P (U|V) as follows:

P(U|V) =\frac{P(U\cap V)}{P(V)}\\=\frac{0}{0.56}\\ =0

Thus, the value of P (U|V) is 0.

(c)

The probability of the union of two events, say A and B, is

P(A\ or\ B)=P(A\cup B)=P(A)+P(B)-P(A\cap B)

Compute the value of P (U or V) as follows:

P(U\ or\ V)=P(U\cup V)\\=P(U)+P(V)-P(U\cap V)\\=0.27+0.56-0\\=0.83

Thus, the value of P (U or V) is 0.83.

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