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castortr0y [4]
3 years ago
10

Write an algebraic expression for "71 more than the product of 184 and d."

Mathematics
1 answer:
Lerok [7]3 years ago
5 0

Answer:

71 + 184d

Step-by-step explanation:

I'm sorry, I don't know how to explain how I got this. I hope it helps though.

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The probability of tossing heads with a standard coin is 1/2, because it is one of two possible outcomes. The probability of tos
spayn [35]

Answer:

  a) 1/64

  b) 1/4096

Step-by-step explanation:

As you can tell from the example, the exponent of 1/2 is the number of heads in a row.

a) p(6 heads in a row) = (1/2)^6 = 1/(2^6) = 1/64

b) p(12 heads in a row) = (1/2)^12 = 1/(2^12) = 1/4096

_____

<em>Additional comment</em>

The probability of a head is 1/2 because we generally are concerned with a "fair coin." That is defined as a coin in which each of the 2 possible outcomes has the same probability, 1/2. Similarly, a "fair number cube" has 6 faces, and the probability of each is defined to be the same as any other, 1/6. Loaded dice and unfair coins do sometimes show up in probability problems.

3 0
2 years ago
Suppose that 15% of the fields in a given agricultural area are infested with the sweet potato whitefly. One hundred fields in t
hram777 [196]

Answer:

a.\mu=15

b.\mu=7.8586 \ and  \ \mu=22.1414

c. Choice A- Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.

Step-by-step explanation:

a.Binomial distribution is defined by the expression

P(X=k)=C_k^n.p^k.(1-p)^{n-k}

Let n be the number of trials,n=100

and p be the probability of success,p=15\%

The mean of a binomial distribution is the probability x sample size.

\mu=np=100\times0.15=15

b.Limits within which p is approximately 95%

sd of a binomial distribution is given as:\sigma=\sqrt npq\\q=1-p

Therefore, \sigma=\sqrt(100\times0.015\times0.85)=3.5707

Use the empirical rule to find the limits. From the rule, approximately 95% of the observations are within to standard deviations from mean.

sd_1=>\mu-2\sigma=15-2\times3.3507=7.8586\\sd_2=>\mu-2\sigma=15+2\times3.3507=22.1414

Hence, approximately 95% of the observations are within 7.8586 and 22.1414 (areas of infestation).

c.  x=45 is not within the limits in b above (7.8586,22.1414). X=45 appears to be a large area of infestation. A.Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.

4 0
3 years ago
Choose the point-slope form of the equation below that represents through the points (-3,2) and (2,1)
s2008m [1.1K]

Answer:

-1/4

Step-by-step explanation:

2-1 over -3-1 = 1/-4

3 0
3 years ago
What is the simplified form of 3V7-5V7? A.-2V7 B.2V7 C.-V14 D.15V7
lesantik [10]

Answer:

A -2V7

Step-by-step explanation:

you just have to subtract the coefficients

3-5=-2

-2V7

3 0
2 years ago
Read 2 more answers
In this problem, how would I find the value of Z ?
BabaBlast [244]

Answer:

z = 30

Step-by-step explanation:

WX and VU are congruent

2z + 10 = z + 45

subtract z from both sides (z + 10 = 45)

subtract 10 from both sides (z = 30)

the answer is z = 30

3 0
3 years ago
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