Answer:
Si
Step-by-step explanation:
Answer:
Step-by-step explanation:
In Δ PQS and ΔPQT
∠QPS = ∠RPT {Common angle}
∠PSQ = ∠PTR = 90° {QS & RT are altitude}
QS = RT {given}
ΔPQS ≅ ΔPRT {A A S congruent}
PQ = PS {CPCT}
So, PQR is an isosceles triangle.
9)
a) Flas card (I) and (iii) are congruent.
b) A S A congruent
c) BC ≅ RP
|a| = b gives
a =b or a = -b
so,
|-x| = -10
gives
-x = -10 or -x = 10
x = 10, -10
now let us verify,
when x = 10, |-10| = +10 and it is not = -10
so, x= 10 is NOT a solution.
when x = -10, |-(-10)| = |10| = 10 and it is not = -10
so, x= -10 is NOT a solution.
hence, this equation does not have a solution.
If we know that |...| can never be negative, we can directly deduce that this equation does not have any solution.
2x + 2(5+x)=10
2x+10+2x=10
4x+10=10
4x=0
X=0