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Novosadov [1.4K]
3 years ago
5

There is a bag with only red marbles and blue marbles. The probability of randomly choosing a red marble is 2 9 . There are 63 m

arbles in total in the bag and each is equally likely to be chosen. Work out how many red marbles there must be.
Mathematics
1 answer:
Tatiana [17]3 years ago
7 0

The main idea is the number of marbles and the denominator of the probability. All you have to do is multiply the fraction by a fraction which is equal to 1 which makes the denominator equal to 63. We know 63 is a multiple of 9. 9 goes 7 times in 63 so we multiple the fraction \frac{2}{9} with \frac{7}{7} which gives, \frac{2 * 7}{9 * 7} which when evaluated gives \frac{14}{63} and the numerator is the number of red marbles in the bag. So there are 14 red marbles in the bag :D

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natima [27]

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Step-by-step explanation:

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3 years ago
Which value of y would make OP ll LN? A 16 B 24 C 32 D 36
Andreyy89

see the attached figure to better understand the problem

we know that

if OP ll LN

then

by proportion

\frac{MO}{ML} =\frac{MP}{MN}

we have that

MO=28\ units \\ML=28+14=42\ units\\MP=y\ units\\MN=(y+18)\ units

substitute

\frac{28}{42} =\frac{y}{(y+18)}\\ \\28(y+18)=42y \\ \\42y-28y=28*18 \\ \\14y=504 \\ \\y=36\ units

therefore

<u>the answer is</u>

The value of y is 36\ units

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3 0
3 years ago
The hexagon GIKMPR is regular. The dashed line segments form 30 degree angles.
Gwar [14]

Answer:

The correct option is (D).

Step-by-step explanation:

It is given that GIKMPR is regular hexagon. It means it has 6 vertices.

Since the central angle is 360 degree. Therefore the central angle between two consecutive vertices is

\frac{360^{\circ} }{6}=60^{\circ}

It is given that the dashed line segments form 30 degree angles.

We have rotated the hexagon about O to map PQ to RF. Since P and R are consecutive vertices, therefore the angle between them is 60 degree.

The vertex R is immediate next to the vertex P in clockwise direction.

So if we rotate the hexagon at 60 degree clockwise about O, then we can maps PQ to RF.

360^{\circ}-60^{\circ}=300^{\circ}

Therefore we can also rotate the hexagon at 300 degree counterclockwise about O, then we can maps PQ to RF.

Therefore option D is correct.


8 0
3 years ago
Which equation could be used to find the perimeter of an isosceles triangle, with two sides 13 cm long, a base 10 cm long, and a
AVprozaik [17]
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4 0
4 years ago
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