Answer:
y=3x-15
Step-by-step explanation:
3x-2y=15
+2y +2y
3x=15+2y
-15 -15
y=3x-15
Answer:
c) (-2, 1)
Step-by-step explanation:
3x - 3y = -9
2x + y = -3
2x + y = -3
-2x -2x
y = -2x - 3
3x - 3y = -9
y = -2x - 3
3x - 3(-2x - 3) = -9
3x + 6x + 9 = -9
9x + 9 = -9
- 9 -9
9x = -18
/9 /9
x = -2
y = -2x - 3
y = -2(-2) -3
y = 4 - 3
y = 1
(x, y) --> (-2,1)
Check your answer:
y = -2x - 3
1 = -2(-2) - 3
1 = 4 - 3
1 = 1
This statement is true
Hope this helps!
1. Start with ΔCIJ.
- ∠HIC and ∠CIJ are supplementary, then m∠CIJ=180°-7x;
- the sum of the measures of all interior angles in ΔCIJ is 180°, then m∠CJI=180°-m∠JCI-m∠CIJ=180°-25°-(180°-7x)=7x-25°;
- ∠CJI and ∠KJA are congruent as vertical angles, then m∠KJA =m∠CJI=7x-25°.
2. Lines HM and DG are parallel, then ∠KJA and ∠JAB are consecutive interior angles, then m∠KJA+m∠JAB=180°. So
m∠JAB=180°-m∠KJA=180°-(7x-25°)=205°-7x.
3. Consider ΔCKL.
- ∠LFG and ∠CLM are corresponding angles, then m∠LFG=m∠CLM=8x;
- ∠CLM and ∠CLK are supplementary, then m∠CLM+m∠CLK=180°, m∠CLK=180°-8x;
- the sum of the measures of all interior angles in ΔCLK is 180°, then m∠CKL=180°-m∠CLK-m∠LCK=180°-(180°-8x)-42°=8x-42°;
- ∠CKL and ∠JKB are congruent as vertical angles, then m∠JKB =m∠CKL=8x-42°.
4. Lines HM and DG are parallel, then ∠JKB and ∠KBA are consecutive interior angles, then m∠JKB+m∠KBA=180°. So
m∠KBA=180°-m∠JKB=180°-(8x-42°)=222°-8x.
5. ΔABC is isosceles, then angles adjacent to the base are congruent:
m∠KBA=m∠JAB → 222°-8x=205°-7x,
7x-8x=205°-222°,
-x=-17°,
x=17°.
Then m∠CAB=m∠CBA=205°-7x=86°.
Answer: 86°.
Answer:
the answer is 6.
Step-by-step explanation:
I know this is not the answer, because i haven’t done this in years.. but the slope formula is m=(y2-y1)/(x2-x1)
i got -5… idek! i’m sorry!
