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3 years ago

Please help me please

Mathematics

2 answers:

denpristay [2]3 years ago

5 0

40-30=10, all you have to do is multiply the 4 case by 10 and 3 by 10 then subtract them to get 40+30=10

Ivenika [448]3 years ago

3 0

10 juice boxes would be left

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I need help please and thank you

Sphinxa [80]

The answer to your problem is 66

6 0

4 years ago

Read 2 more answers

How do you solve this?

shutvik [7]

Answer: X=5

Step-by-step explanation:

-8=(X+11)/-2

* start by multiplying both sides by -2

16=X+11

*subtract 11 from both sides

5=X

5 0

4 years ago

Write the point-slope form of the equation of the line that passes through the points (6, -9) and (7, 1). Include your work in y

Taya2010 [7]

<h3>y + 9 = 10(x - 6) is the point-slope form of the equation of the line that passes through the points (6, -9) and (7, 1)</h3>

Solution:

Given points are:

(6, -9) and (7, 1)

Let us find the slope of line

$m = \frac{y_2-y_1}{x_2-x_1}$

From given,

$(x_1, y_1) = (6,-9)\\\\(x_2, y_2) = (7, 1)$

Therefore,

$m = \frac{1+9}{7-6}\\\\m = \frac{10}{1}\\\\m = 10$

Thus slope of line is 10

The point slope form of line is given as:

$y - y_1 = m(x-x_1)$

Substitute m = 10 and $(x_1, y_1)$ = (6, -9) in above

$y + 9 = 10(x - 6)$

Thus the equation of line in point slope form is found

6 0

3 years ago

Which of the following would best be solved using factoring the difference of squares? 2² + 3x - 10 = 0 O 3r² + 12x = 8 2³ +52²

IgorC [24]

Given: Different equations

To Determine: Which would be best solved using difference of two squares

Solution

The factorization of a difference of two squares is given below

$a^2-b^2=(a-b)(a+b)$

Let us examine each of the given equation

$\begin{gathered} x^2+3x-10=0 \\ x^2-2x+5x-10=0 \\ x(x-2)+5(x-2)=0 \\ (x-2)(x+5)=0 \end{gathered}$ $\begin{gathered} 3x^2+12x=8 \\ 3x^2+12x-8=0 \end{gathered}$ $\begin{gathered} x^3+5x^2-9x-45=0 \\ x^2(x+5)-9(x+5)=0 \\ (x+5)(x^2-9)=0 \\ x^2-9=x^2-3^2=(x+3)(x-3) \\ Therefore \\ (x+5)(x+3)(x-3)=0 \end{gathered}$ $\begin{gathered} x^2-25=0 \\ x^2-5^2=0 \\ (x+5)(x-5)=0 \end{gathered}$

From the above,

$\begin{gathered} x^3+5x^2-9x-45=0 \\ AND \\ x^2-25=0 \end{gathered}$

The two equation above can be solved by difference of two square, but the equation below is the easiest solved using differnce of two square

x² - 25 = 0

3 0

1 year ago

Simplify the algebraic expression: 4x + 8y + 7x² + 5x – 2y.

-BARSIC- [3]

Answer:

7x² + 9x + 6y

Step-by-step explanation:

7x² + 4x + 5x + 8y - 2y

5 0

3 years ago