Question

Find the x-intercepts of the parabola with vertex (5,-4) and y-intercept (0,96). Write your answer in this form: (x1,y1),(x2,y2). If necessary, round to the nearest hundredth. ​

Answer 1

Answer:

The x-intercepts are

(x1,y1)=(4,0)

(x2,y2)=(6,0)

Step-by-step explanation:

we know that

The equation of the given parabola is

$(y-k)=a(x-h)^{2}$

we have

the vertex is the point (5,-4)

substitute

$(y+4)=a(x-5)^{2}$

The y-intercept is the point (0,96)

substitute and solve for a

$(96+4)=a(0-5)^{2}$

$100=a(25)$

$a=100/25=4$

The equation of the vertical parabola is equal to

$(y+4)=4(x-5)^{2}$

Find the x-intercepts

Remember that

The x-intercepts are the values of x when the value of y is equal to zero

For y=0

$4=4(x-5)^{2}$

Simplify

$1=(x-5)^{2}$

Rewrite

$(x-5)^{2}=1$

square root both sides

$(x-5)=(+/-)1$

$x=(+/-)1+5$

$x=(+)1+5=6$

$x=(-)1+5=4$

therefore

The x-intercepts are

(x1,y1)=(4,0)

(x2,y2)=(6,0)