Given:
In a right angle triangle θ is an acute angle and
.
To find:
The value of
.
Solution:
In a right angle triangle,

We have,

It means the ratio of perpendicular to base is 3:5. Let 3x be the perpendicular and 5x be the base.
By using Pythagoras theorem,





In a right angle triangle,



Therefore, the value of
is
.
Answer:
In interval notation it is ( -∞, ∞).
Step-by-step explanation:
All values of x can be input to this function.
If all were children, revenue would be 700*$7 = $4900. Revenue is actually $6400 -4900 = $1500 more than that. Each adult admission that replaces a child's admission adds $10 -7 = $3 to the revenue, so there must have been
$1500/$3 = 500 . . . . adult admissions
There were 200 children at the show.
There were 500 adults at ths show.
Answer:
The slope is 1
Step-by-step explanation:
Slope = (y₂-y₁)/(x₂-x₁) = (2-3)/(4-5) = (-1)/(-1) = 1
Therefore, the slope of the line that passes through (5,3) and (4,2) is 1
Answer:
(a) 9.9321*10^{-11}
(b) 6.0498*10^{-11}
(c) 7.7120^{-11}
(d) 1.6417 times more probable
Step-by-step explanation:
(a) The probability of winning a 6/49 lottery is given by:

(b) The probability of winning a 6/53 lottery is given by:

(c) The probability of winning a 6/51 lottery is given by:

(d) The ratio between the probabilities of winning the 6/49 lottery and winning the 6/53 lottery is:

It is 1.6417 times more probable.