Helppp me pleaseee due tonight

What is the solution of the linear system shown in the graph below?

Serga [27]

Solution would be where the two lines intersect but they never do. They are parallel and never meet

Answer: no solution

6 0

3 years ago

Easy one - giving brainly if correct - show work.

astra-53 [7]

Answer:

47. 1 5/8

48. 1 1/12

Step-by-step explanation:

47.

First, convert the denominators to be the same.

8 1/2 minutes, Ruby's mile time, can be converted to 8 4/8.

Then subtract.

8 4/8 - 6 7/8 = 1 5/8

48.

Make sure the denominators are the same. Both denominators can be multiplied by 3 or 4 to become 12.

1 1/4 can be multiplied by 3 to get 1 3/12. And 1 1/3 can be multiplied by 4 to get 2 4/12.

Then subtract.

2 4/12 - 1 1/3 = 1 1/12

6 0

2 years ago

Find the solution for the system of equations -4x-2y=-12 4x +8y=-24

valkas [14]

6y=-36
y=-6
-4x+12=-12
-4x=24
x=-6

6 0

3 years ago

Read 2 more answers

Amrita bought a new delivery van for $32,500. The value of this van depreciates at a rate of 12% each year. Write a function f(x

FrozenT [24]

Answer:

The function, f(x) to model the value of the van can be expressed as follows;

$f(x) = 32,500 \times \left(0.88\right)^x$

Step-by-step explanation:

From the question, we have;

The amount at which Amrita bought the new delivery van, PV = $32,500

The annual rate of depreciation of the van, r = -12% per year

The Future Value, f(x), of the van after x years of ownership can be given according to the following formula

$f(x) = PV \cdot \left(1 + \dfrac{r}{100} \right)^x$

Therefore, the function, f(x) to model the value of the van after 'x' years of ownership can be expressed as follows;

$f(x) = 32,500 \cdot \left(1 - \dfrac{12}{100} \right)^x = 32,500 \cdot \left(0.88\right)^x$

8 0

3 years ago

Dual-energy X-ray absorptiometry (DXA) is a technique for measuring bone health. One of the most common measures is total body b

sesenic [268]

Answer:

$\bar d=\frac{\sum_{i=1}^n d_i}{n}=-0.001$

$s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}=0.0095$

-The sample is too small to make judgments about skewness or symmetry.

H0: $\mu_{1}=\mu_{2}$

H1: $\mu_{1} \neq \mu_{2}$

$t=\frac{1.173-1.174}{\sqrt{\frac{0.1506^2}{8}+\frac{0.1495^2}{8}}}=-0.013$

$p_v =2*P(t_{(14)}$

So the p value is a very high value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and a we don't have a significant difference between the two means.

Step-by-step explanation:

First we need to find the difference defined as:

(Operator 1 minus Operator 2)

d1=1.326-1.323=0.003 d2=1.337-1.322=0.015

d3=1.079-1.073=0.006 d4=1.229-1.233=-0.004

d5=0.936-0.934=0.002 d6=1.009-1.019=-0.01

d7=1.179-1.184=-0.005 d8=1.289-1.304=-0.015

Now we can calculate the mean of differences given by:

$\bar d=\frac{\sum_{i=1}^n d_i}{n}=-0.001$

And for the sample deviation we can use the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}=0.0095$

Describe the distribution of these differences using words. (which one is correct)

We can plot the distribution of the differences with the folowing code in R

differences<-c(0.003,0.015,0.006,-0.004,0.002,-0.01,-0.005,-0.015)

hist(differences)

And we got the image attached. And we can see that the distribution is right skewed but we don't have anough info to provide a conclusion with just 8 differnences.

-The sample is too small to make judgments about skewness or symmetry.

Use a significance test to examine the null hypothesis that the two operators have the same mean. Give the test statistic. (Round your answer to three decimal places.)

$\bar X_{1}=1.173$ represent the mean for the operator 1

$\bar X_{2}=1.174$ represent the mean for the operator 2

$s_{1}=0.1506$ represent the sample standard deviation for the operator 1

$s_{2}=0.1495$ represent the sample standard deviation for the operator 2

$n_{1}=8$ sample size for the operator 1

$n_{2}=8$ sample size for the operator 2

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the means for the two groups are the same, the system of hypothesis would be:

H0: $\mu_{1}=\mu_{2}$

H1: $\mu_{1} \neq \mu_{2}$

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

We can replace in formula (1) like this:

$t=\frac{1.173-1.174}{\sqrt{\frac{0.1506^2}{8}+\frac{0.1495^2}{8}}}=-0.013$

Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test. The first step is calculate the degrees of freedom, on this case:

$df=n_{1}+n_{2}-2=8+8-2=14$

Since is a bilateral test the p value would be:

$p_v =2*P(t_{(14)}$

So the p value is a very high value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and a we don't have a significant difference between the two means.

8 0

3 years ago