Answer:
Step-by-step explanation:
<u>Biquadratic Equations</u>
Solve:
The biquadratic equations are equations of degree 4 without the terms of degree 1 and 3.
Solving such equations requires to express the equation as a second-degree equation with as the variable.
Rewriting the equation:
The quadratic equation can be factored as:
It leads to two equations:
The first equation has imaginary roots. Solving for x:
Where
The second equation has two real roots:
The roots are:
Answer:
I'm really sorry I can't tell you the answer because you have to measure the angle by yourself using a protractor. But I gave you information about types of angles if you got the degree of angles ( e.g 90 degrees). Hope it helped.
Step-by-step explanation:
acute angle-an angle between 0 and 90 degrees
right angle-an 90 degree angle
obtuse angle-an angle between 90 and 180 degrees
straight angle-a 180 degree angle
Answer: The zeroes of this function are x = 0 (which has a multiplicity of 1) and x = -3 (which has a multiplicity of 2) The graph of this function will be attached. Lastly, (-1, -4) is the local minima and (-3, 0) is the local maxima. I hope this has helped :)
Answer:
One root is 90 degrees or π/2 radians.
Drawing a graph we get all the roots:
nπ and π(n - 1/2)
Step-by-step explanation:
Sin^3A.cos A + Cos^ 3 A = Cos A
Divide through by cos A
sin^3A + cos^2A = 1
sin^3 A = 1 - cos^2 A
sin^3 A = sin^2 A
sin A = 1
So one root is A = 90 degrees or π/2 radians.
Checking this result:
(sin 90^3 * cos 90 + (cos 90)^3 = 1 * 0 + 0 = 0
cos 90 = 0
So this is correct..
Answer:A,C
Step-by-step explanation: