Answer:
Draw it with 9 cm for length and width.
Step-by-step explanation:
The product is the maximum area when the length and width are as close as possible, or equal to each other. Because length and width are 2 sides each, we can divide 36 by 4, which is 9.
9x9 = 81 cm^2. This is the largest area possible.
120 square inches because a circle is 360 degrees so there will be 6 60 degree sections in it and each 60 degree section needs 20 square inches to cover it so 6 x 20= 120
Answer:
In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).
Step-by-step explanation:
There is really no need to use any quadratics or roots.
( Consider the same problem on the plain number line first. )
How do you find the number between 2 and 5 which is twice as far from 2 as from 5?
You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get
4=2+23(5−2)
It works completely the same with geometric points (using vector operations), just linear interpolation: Call the result R, then
R=P+23(Q−P)
so in your case we get
R=(0,−1)+23(3,3)=(2,1)
Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)
Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get
s=a+b=2b+b=3b
⇔b=13s⇒a=23s
is a characteristic solution to the ODE, and the general solution would be