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3 years ago

-3(x-2)=9(x+8) how do I solve for x?

Mathematics

2 answers:

choli [55]3 years ago

6 0

Answer:x=-5.5

Step-by-step explanation:

schepotkina [342]3 years ago

5 0

Answer:

26=x

Step-by-step explanation:

well you need to do the distributive property.

-3(x-2) = -6x+6

9(x+8) = 9x+72

-6x+6=9x+72

now you subtract -6x from -6x and 9x

and add 72 to 6

-6x +6 =9x + 72

-6x + 72 -6x -72

78=3x

divide them both by 3

26=x

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The admission fee at the steamboat springs hot air balloon festival is $1.50 for children and $4.00 for adults. On a certain day

GaryK [48]

Answer:

Number of child tickets = 800

Number of adult tickets = 330

Step-by-step explanation:

Let c = number of child tickets

and a= the number of adult tickets.

We are given:

The admission fee at the steamboat springs hot air balloon festival is $1.50 for children and $4.00 for adults.

On a certain day, 1,130 enter the festival and 2, 520 is collected.

Making equations:

$c+a=1130$ (because total people entered are 1130, so adding number of adult and child tickets will give us total number of people)

$1.50c+4.00a=2520$ (because total money collected is 2520, so adding coat of adult and child tickets will give us total money)

Now, solving these equations simultaneously, we can find values of x and y

Let:

$c+a=1130--eq(1)\\1.50c+4.00a=2520--eq(2)$

From equation 1 find value of c and put it in eq(2)

$c+a=1130\\c=1130-a$

Putting value of c in eq(2)

$1.50c+4.00a=2520\\Put\:c=1130-a\\1.5(1130-a)+4a=2520\\1695-1.5a+4a=2520\\-1.5a+4a=2520-1695\\2.5a=825\\a=\frac{825}{2.5}\\a=330$

So, we get value of a = 330

Now, punting value of a in eq(1) to get value of c

$c+a=1130\\c+330=1130\\c=1130-330\\c=800$

So, we get value of c = 800

Therefore:

Number of child tickets = c= 800

Number of adult tickets = a = 330

4 0

3 years ago

Suppose that the mean and standard deviation of the scores on a statistics exam are 78 and 6.11, respectively, and are approxima

kiruha [24]

Answer:

0.7422 = 74.22% of scores are above 74.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 78, \sigma = 6.11$