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Tpy6a [65]
4 years ago
12

Factorize 216x^3 + 64y^3

Mathematics
1 answer:
marin [14]4 years ago
5 0

Answer:

8( 3x+2y) ( 9x^2 -6xy +4y^2)

Step-by-step explanation:

216x^3 + 64y^3

Factor out the greatest common factor of 8

8( 27x^3 +8y^3)

Rewriting

8 ( (3x)^3 + (2y)^2))

Recognizing this as the difference of cubes)

a^3 + b^3 = (a+b) (a^2-ab+b^2)

8 ( (3x)^3 + (2y)^2)) = 8( 3x+2y) ( 9x^2 -(3x)(2y) +4y^2)

                                 =8( 3x+2y) ( 9x^2 -6xy +4y^2)

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If a rectangular. Prism. Has 5cm. 10cm on one side and 4cm on the. Other. What is the volume of the rectangle?
emmasim [6.3K]

Answer: 200\ cm^3

Step-by-step explanation:

Given

The dimension of the rectangular prism is

l=5\ cm\\w=10\ cm\\h=4\ cm

The volume of the prism is given by V=l\times w\times h

\Rightarrow V=5\times 10\times 4\\\Rightarrow V=200\ cm^3

Therefore, the volume of the prism is 200\ cm^3.

7 0
3 years ago
∠A and \angle B∠B are supplementary angles. If m\angle A=(4x-30)^{\circ}∠A=(4x−30)
user100 [1]

Answer:

the measure of ∠A. is 87∘

Step-by-step explanation:

Two angles are said to be supplementary angles if the sum of those angles is 180 degrees.

_________________________________________________

Given

∠A=(4x−30) ∘

∠B=(4x−14) ∘

Fir angles to be supplementary

∠A + ∠B = 180

(4x−30) ∘ + (4x−14) ∘ = 180∘

(8x -54 )∘ = 180∘

=> 8x =  180∘ +  54∘= 234∘

=> x = 234∘/8 = 29.25∘

Thus,

∠A=(4x−30) ∘

∠A=(4*29.25−30) ∘ =( 117 - 30 ) ∘ = 87∘

Thus,

the measure of ∠A. is 87∘

3 0
4 years ago
Answer Please!!! :)<br> Express 2 2/5 As A Decimal Number!!!
barxatty [35]
The decimal 2 2/5 is 2.4


8 0
3 years ago
Factor the polynomial 3x4 - 2x2 + 15x2 - 10 by grouping
Hunter-Best [27]

Answer:

(x2 + 5)(3x2 - 2)

Step-by-step explanation:

x2(3x2 - 2) +5 (3x2 - 2)

=(x2 + 5)(3x2 - 2)

4 0
4 years ago
what are the coordinate points of A’,B’, and C’ after they were translated right 4 units and up 1 unit??
Alisiya [41]

Answer:

A' = ( -2 , 6 )

B' = ( 7 , 3 )

C' = ( 4 , 0 )

Step-by-step explanation:

Itz askin that if each point is to be shifted 4 units right & 1 unit up then what's the co-ordinates of the new points .

The initial point of A = ( -6 , 5 )

When we shift A for 4 units right , the its abscissa = -6 + 4 = -2 (∵ Right side is considered as positive. So that's why it's +4 )

When we shift A for 1 unit up , its ordinate = 5 + 1 = 6 (∵ Upper side is considered as positive. So that's why it's +1 )

Hence , co-ordinates of A' = ( -2 , 6 )

The initial point of B = ( 3 , 2 )

When we shift A for 4 units right , the its abscissa = 3 + 4 =  7

When we shift A for 1 unit up , its ordinate = 2 + 1 = 3

Hence , co-ordinates of B' = ( 7 , 3 )

The initial point of C = ( 0 , -1 )

When we shift A for 4 units right , the its abscissa = 0 + 4 =  4

When we shift A for 1 unit up , its ordinate = -1 + 1 = 0

Hence , co-ordinates of C' = ( 4 , 0 )

5 0
4 years ago
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