Question

For a trapezoid with a height of 7 centimeters and base lengths of 6 centimeters and 10 centimeters, the area is

Answer 1

$\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=6\\ b=10\\ h=7 \end{cases}\implies A=\cfrac{7(6+10)}{2} \\\\\\ A=\cfrac{7(16)}{2}\implies A=7(8)\implies A=56$

Answer 2

Answer:

56

Step-by-step explanation:

$A=\frac{1}{2} (b1+b2)h$

$A=\frac{1}{2} (6+10)7$

$A=\frac{1}{2} (16)7$

$A=8*7$

$A=56$