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Hunter-Best [27]
2 years ago
9

Someone please help me ASAP because I am really stuck thank uuuuu!!!!!

Mathematics
2 answers:
Morgarella [4.7K]2 years ago
7 0
81/200 is the answer
xeze [42]2 years ago
7 0

Answer:

2 3/10

Step by step explanation:

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A) equal lines<br> B) parallel lines<br> C) perpendicular lines<br> D) None of the above
Nat2105 [25]
I think the answer is D, None of the above
8 0
3 years ago
Read 2 more answers
Pulse rates of women are normally distributed with a mean of 77.5 beats per minute and a standard deviation of 11.6 beats per mi
irakobra [83]

Answer:

a) Mean=0 and Standard deviation=1

b) The z-scores have no units of measurement

Step-by-step explanation:

When we convert all the pulse rates of women to z-scores using the formula;

z=\frac{x-\mu}{\sigma} the mean is 0 and the standard deviation is 1.

The reason is that, the resulting distribution of z-scores forms a normal distribution which has a mean of 0 and a standard deviation of 1.

b) The z-scores are standardize scores and has no units of measurement. They give us how many standard deviations below or above the mean of the corresponding values.

8 0
3 years ago
Which of the following statements about JK and JL is true?
bulgar [2K]

Answer:

14

Step-by-step explanation:

5 0
3 years ago
Please answer will mark as brainist!
lana66690 [7]

Answer:

b

Step-by-step explanation:

5 0
2 years ago
50 students live in a dormitory. The parking lot has the capacity for 30 cars. Each student has a car with probability 12 , inde
Maurinko [17]

Answer:

P(X is greater than 30) = 0.06

Step-by-step explanation:

Given that:

Sample proportion (p) = 0.5

Sample size = 30

The Binomial can be approximated to normal with:

\mu = np = 50 \times 0.5 \\ \\ \mu= 25

\sigma = \sqrt{np(1-p) } \\ \\  \sigma = \sqrt{50 \times (0.5)(1-0.5) } \\ \\ \sigma = 3.536

To find:

P(X> 30)

So far we are approximating a discrete Binomial distribution using the continuous normal distribution. 30 lies between 29.5 and 30.5

Normal distribution:

x = 30.5, \mu = 25, \sigma = 3.536

Using the z test statistics;

z = \dfrac{x - \mu}{\sigma}

z = \dfrac{30.5 - 25}{3.536}

z = \dfrac{5.5}{3.536}

z = 1.555

The p-value for P(X>30) = P(Z > 1.555)

The p-value for P(X>30) = 1 - P (Z< 1.555)

From the z tables;

P(X> 30) = 1 - 0.9400

Thus;

P(X is greater than 30) = 0.06

7 0
2 years ago
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