2 because the difference in the equation must equal 0 so it must equal 6 so 6/3 is 2. Therefore the answer is 2
The lower quartile is quartile 1. The graph shows it as "-4". So the answer is D.
Answer:
![\large\boxed{4\sqrt[3]{64}=16}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B4%5Csqrt%5B3%5D%7B64%7D%3D16%7D)
Step-by-step explanation:
![\sqrt[3]{a}=b\iff b^3=a\\\\4\sqrt[3]{64}=(4)(4)=16\\\\\sqrt[3]{64}=4\ \text{because}\ 4^3=64](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Ba%7D%3Db%5Ciff%20b%5E3%3Da%5C%5C%5C%5C4%5Csqrt%5B3%5D%7B64%7D%3D%284%29%284%29%3D16%5C%5C%5C%5C%5Csqrt%5B3%5D%7B64%7D%3D4%5C%20%5Ctext%7Bbecause%7D%5C%204%5E3%3D64)
Answer:
64 m, at time t = 4 sec
Step-by-step explanation:
We must maximize the function h = 32t – 4t^2. One way in which to do this is to find the axis of symmetry, t = -b / [2a], and from that calculate the height:
a = -4, b = 32, c = 0
-32
and therefore the axis of symmetry is t = ---------------- = 4
2(-4)
The height, h, at time t = 4, is h(4) = 32(4) - 4(4)^2 = 64 m
The maximum height of the ball is 64 m, at time t = 4 sec
