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maw [93]
3 years ago
12

ASHANTI AND MARIA WENT TO THE STORE TO BUY SNACKS FOR THEIR BACK TO SCHOOL PARTY. THEY BOUGHT BAGS OF CHIPS,PRETZELS,NACHOS. THE

Y BOUGHT FOUR TIMES AS MANY BAGS OF PRETZELS AS BAGS OF CHIPS, AND THREE FEWER BAGS OF NACHOS THAN BAGS OF PRETZELS. IF x REPRESENTS THE NUMBER OF BAGS OF CHIPS THEY BROUGHT, EXPRESS, IN TERMS OF x, HOW MANY BAGS OF SNACKS THEY BROUGHT IN ALL
Mathematics
1 answer:
MissTica3 years ago
3 0

Answer:X(2X-23)/(X-12)


Step-by-step explanation:

C = Chips = X

P = Pretzels

N = Nachos


First: X  (number of bags of Chips)

Second: 4P=X  (number of bags of pretzels)

Third: P=(P-3)N (number of bags of Nachos)

we need to simplify them and add them.

they bought:

X + 4P + (P-3)N in total


from the Nachos we can see: N= P/(P-3)

and from the Pretzels: 4P=X       X=4P     Therefore P=X/4

Also: N=(X/4)/((X/4)-3)

Replace:

X+ X + (X/4)/ ((X/4)-3)

2X+ 4/X/((X/4)-3) = 2X+(X/4)/((x-12)/4)

2X+X/4*4/(X-12)

2X+X/(X-12)

(2X*(X-12)+X)/(X-12)

(2X^2-24X+X)/(X-12)

X*(2X-23)/(X-12)



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The distance that a spring will stretch varies directly as the force applied to the spring. A force of 8080 pounds is needed to
Nimfa-mama [501]

Answer:

176 199 pounds

Step-by-step explanation:

To answer this it is first useful to find the proportionality constant.

F= kx

8080 pounds = k.88 in

k = 91.81 pound/inch

So what force is required to stretch the spring to 1919 inches?

F = kx

  = 91.81 pound/inch * 1919 inches

  = 176 199 pounds

It is worth noting that this force seems rather large and the spring might have long reached its elastic limit

7 0
3 years ago
Need help ASAP please and thank you!
erik [133]

Answer:

I believe that the answer is 153 units^2.

9*10=90

And then 9*7=63, since there are two of the same triangle, we don't have to divide by 2.

So, 90+63=153.

I hope this helps!

7 0
3 years ago
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Gethen drinks 48 fluid ounces of water in 1 day.He needs to drink 8 cups in total.How many more cups does he need to drink?
kvv77 [185]

Answer:

2 Cups

Step-by-step explanation:

6 0
3 years ago
Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior citizen tickets and 4 child ticke
FrozenT [24]

Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?

14S + 4C = 200

14S = 200 - 4C

S = (200 - 4C)/14

7S + 1C = 92

7S = 92 - C

S = (92 - C)/7

(200 - 4C)/14 = (92 - C)/7

7 x (200 - 4C) = 14 x (92 - C)

1400 - 28C = 1288 - 14C

1400 - 1288 = 28C - 14C

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8 0
3 years ago
The perimeter of a rectangular field is
Andre45 [30]
346 divided by 2 would be 153. Subtract 92, and that would lead you with 61.
Therefore, the ultimate answer is 61.
8 0
3 years ago
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