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maw [93]
3 years ago
12

ASHANTI AND MARIA WENT TO THE STORE TO BUY SNACKS FOR THEIR BACK TO SCHOOL PARTY. THEY BOUGHT BAGS OF CHIPS,PRETZELS,NACHOS. THE

Y BOUGHT FOUR TIMES AS MANY BAGS OF PRETZELS AS BAGS OF CHIPS, AND THREE FEWER BAGS OF NACHOS THAN BAGS OF PRETZELS. IF x REPRESENTS THE NUMBER OF BAGS OF CHIPS THEY BROUGHT, EXPRESS, IN TERMS OF x, HOW MANY BAGS OF SNACKS THEY BROUGHT IN ALL
Mathematics
1 answer:
MissTica3 years ago
3 0

Answer:X(2X-23)/(X-12)


Step-by-step explanation:

C = Chips = X

P = Pretzels

N = Nachos


First: X  (number of bags of Chips)

Second: 4P=X  (number of bags of pretzels)

Third: P=(P-3)N (number of bags of Nachos)

we need to simplify them and add them.

they bought:

X + 4P + (P-3)N in total


from the Nachos we can see: N= P/(P-3)

and from the Pretzels: 4P=X       X=4P     Therefore P=X/4

Also: N=(X/4)/((X/4)-3)

Replace:

X+ X + (X/4)/ ((X/4)-3)

2X+ 4/X/((X/4)-3) = 2X+(X/4)/((x-12)/4)

2X+X/4*4/(X-12)

2X+X/(X-12)

(2X*(X-12)+X)/(X-12)

(2X^2-24X+X)/(X-12)

X*(2X-23)/(X-12)



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Since there are three negative numbers your product will be negative.
6.5 * 4 = 26.0
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52
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72.8
Answer is -72.8
8 0
3 years ago
Pls help pls helppp i will giving breanlist
GaryK [48]

Answer:

[-5, 4) ∪ (4, ∞)

Step-by-step explanation:

Given functions:

f(x)=\dfrac{1}{x-3}

g(x)=\sqrt{x+5}

Composite function:

\begin{aligned}(f\:o\:g)(x)&=f[g(x)]\\ & =\dfrac{1}{\sqrt{x+5}-3} \end{aligned}

Domain: input values (x-values)

For (f\:o\:g)(x) to be defined:

x+5\geq 0 \implies x\geq -5

\sqrt{x+5}\neq 3 \implies x\neq 4

Therefore, -5\leq x < 4  and  x > 4

⇒  [-5, 4) ∪ (4, ∞)

3 0
2 years ago
Approximate the value of the square root of 110 to the nearest hundredth
DaniilM [7]

Answer:

10.4900

Step-by-step explanation:

pls make a brainliest

3 0
3 years ago
Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.
o-na [289]

Answer: \text{Length of AG=}\frac{2\sqrt{63}}{3}

Explanation:  

Please follow the diagram in attachment.  

As we know median from vertex C to hypotenuse is CM  

\therefore CM=\frac{1}{2}AB

We are given length of CG=4  

Median divide by centroid 2:1  

CG:GM=2:1  

Where, CG=4

\therefore GM=2 ft

Length of CM=4+2= 6 ft  

\therefore CM=\frac{1}{2}AB\Rightarrow AB=12

In \triangle ABC, \angle C=90^0

Using trigonometry ratio identities  

AC=AB\sin 30^0\Rightarrow AC=6 ft

BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3} ft  

CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3} ft

In \triangle CAN, \angle C=90^0  

Using pythagoreous theorem  

AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}

Length of AG=2/3 AN

\text{Length of AG=}\frac{2\sqrt{63}}{3} ft


5 0
3 years ago
Please help asap, will mark brainlest. Thanks
mixer [17]

Answer:

2.

4x^2 + 4 - 5x + x - 2x^2 + 8

= (4x^2 - 2x^2) + (x - 5x) + (4 + 8)

= 2x^2 - 4x + 12

=> D is correct

3.

2x^2 + 6x - 7x + 8 - 3x^2 + 1

= (2x^2 - 3x^2) + (6x - 7x) + (1 + 8)

= -x^2 - x + 9

=> C is correct

4.

B is correct (4 and 3)

Hope this helps!

:)

3 0
3 years ago
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