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MrRa [10]
3 years ago
11

Rewrite terms that are subtracted as addition of the opposite. g2 + (–4g4) + 5g + 9 + (–3g3) + 3g2 + (–6) Group like terms. Comb

ine like terms. Write the resulting polynomial in standard form.
Mathematics
1 answer:
Vilka [71]3 years ago
3 0

Answer:

-4g^4 -3g^3 + 4g^2 +5g +3

Step-by-step explanation:

g^2 + -4g^4 +5g +9 -3g^3 + 3g^2 -6

-4g^4 -3g^3 + 4g^2 +5g +3

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jenyasd209 [6]

Answer:

2 ( 3²x² - 5² )

Step-by-step explanation:

it is the answer

7 0
3 years ago
A car is on a driveway that is inclined 10 degrees to the horizontal. A force of 490 lb is required to keep the car from rolling
lara31 [8.8K]

Answer:

a) weight  of the car = 2816,1 lbs

b) 2773 lbs

Step-by-step explanation:

The equilibrium force is 490 lbs. That force keep the car at rest, then

∑ Fy  =  0     and  ∑Fx  =  0

Forces acting on the car:

The external force   490 lbs

weight of the car   uknown

Normal force

sin∠10°  =  0,174

cos∠10° = 0.985

∑Fx  =  0         mg*sin10°- 490 = 0      ∑Fy =  0      mg*cos10° - N  =  0

mg*0,174= 490

mg  =  490 / 0,174

mg = 2816,1 lbs

weight  of the car = 2816,1 lbs

The Normal force

mg*cos10° - N  =  0        2816,1 * 0,985 = N

N = 2773 lbs

Then equal force in magnitude and in opposite direction will car exets on the driveway

3 0
3 years ago
Calculate the slope of the line that passes through (12,15) and (10, 21). Reduce answer to lowest terms if
gulaghasi [49]

Answer:

-3

Step-by-step explanation:

Slope is rise divided by run. Y2-Y1 Divided by X2-X1

You get 6 divided by -2

-3

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