All categories

3 years ago

A driving moving at 22m/s stops the car in 2s. find the stopping distance

Mathematics

1 answer:

Kaylis [27]3 years ago

8 0

Step-by-step explanation:

Hey there!

Here,

Speed = 22m/s

Time = 2 s.

Distance = ?

We have;

$d = s \times t$

$d = \frac{22m}{s} \times 2 \: s$

Cancel "s" and multiply 22 to 2 ,we will get;

Distance = 44m.

Therefore, distance = 22m.

Hope it helps..

You might be interested in

You can perform 10 push ups in 25 seconds how many can you do in 2 minutes

Whitepunk [10]

not the GREATEST at math but try 50

6 0

3 years ago

Please help me due today easy question

Kitty [74]

Answer:

$24.00 dollars. The problem is confusing, so sorry if this is wrong.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

An election campaign organizer bought 20,000 buttons to hand out for her candidate. The organizer handed out 14,000 of the butto

notsponge [240]

Answer:

help me

Step-by-step explanation:

3 0

3 years ago

Solve the system of equations. - 4x + 3y = -2 y=r-1 y= x=

sergij07 [2.7K]

Answer:

culo

Step-by-step explanation:

6 0

2 years ago

You are going to estimate how long a person holds down a button on their calculator by randomly selecting people and asking them

Ray Of Light [21]

Answer:

You need to have 538 people in your study.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.94}{2} = 0.03$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.03 = 0.97$ , so Z = 1.88.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

You practiced on the people at work and found a standard deviation of about 0.37 seconds.

This means that $\sigma = 0.37$

You want to get a 94% confidence interval that is only 0.06 in width.

This means that $M = \frac{0.06}{2} = 0.03$

How many people do you need to have in your study?

This is n for which M = 0.03. So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.03 = 1.88\frac{0.37}{\sqrt{n}}$

$0.03\sqrt{n} = 1.88*0.37$

$\sqrt{n} = \frac{1.88*0.37}{0.03}$

$(\sqrt{n})^2 = (\frac{1.88*0.37}{0.03})^2$

$n = 537.6$

Rounding up:

You need to have 538 people in your study.

7 0

2 years ago