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2 years ago

To solve the equation 6x + 3 = 9 for x, what operations must be

Mathematics

1 answer:

Karolina [17]2 years ago

8 0

Answer:

Subtraction, and then division.

Step-by-step explanation:

We would subtract 3 on each side to undo the '3', and then divide by 6 on both sides to isolate 'x'.

$6x+3 = 9\\\\6x + 3 - 3 = 9 - 3\\\\ 6x = 6\\\\\frac{6x=6}{6}\\\\\boxed{x=1}$

Hope this helps.

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If m<9=97 and m<12=114, find each measure.

seropon [69]

Answer:

a. 97

b. 83

c.66

d. 114

e.83

f. 97

g. 114

h.66

i. 83

j. 66

k.83

l.97

m. 114

n. 66

6 0

3 years ago

Find the area of the circle with the given diameter. d = 28 inches

alexdok [17]

Answer: 196pi in.^2

Step-by-step explanation:

Divide the diameter by two.

You would get 14, then square it, you would get 196.

4 0

3 years ago

Inverse laplace of [(1/s^2)-(48/s^5)]

Katen [24]

**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform $F(s)$ and $G(s)$ , then $\mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}$

Given that $\dfrac{1}{s^2} = \dfrac{1!}{s^2}$ and $-\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}$

From Table of Laplace Transform, you have $\mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}}$ and hence $\mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}$ .

Hope this helps...

7 0

3 years ago

What do you do to both sides to r? What is r? 3/8 r = 6 HELP ME

faust18 [17]

Answer:

r = 16

Step-by-step explanation:

$\frac{3}{8}r = 6 \\\\$

Multiply both sides by 8

$8*\frac{3}{8}r = 6*8\\\\3r = 48\\$

Divide both side by 3

$\frac{3}{3}r=\frac{48}{3}\\\\r = 16$

Multiply both side by (8/3)

$\frac{8}{3}*\frac{3}{8}r=6*\frac{8}{3}\\\\r = 2*8\\\\r = 16$

write an equation to represent the information in this problem. Jerel runs five days each week. on each of 4 days, he runs 2.3 km. if jerel runs a total of 14km, how many kilometers does he run on the fifth day?

Let x be the distance run on the fifth day

Total distance run on all the four days = 2.3 * 4 = 9.2 km

Required equation : x + 9.2 = 14

x = 14 - 9.2

x = 4.8 km

3 0

2 years ago

Molly's favorite store is running a great deal. All products are marked down 20% from their original

Black_prince [1.1K]

Answer:

D. 0.8p(1p-0.2p)

Step-by-step explanation:

If p is the original price, the markdown price is:

p - 20% =
p - p(20/100) =
p - 0.2p =
0.8p

Now, another 20% off:

0.8p - 20% =
0.8p - 0.8p(20/100) =
0.8(p - 0.2p) =
0.64p

Answer choices:

A. 0.2(1p-0.2p)
B. 0.6p
C. (1p-0.2p)-0.2p
D. 0.8p(1p-0.2p)

Correct one is D

8 0

2 years ago