Question

Considere os logaritmos log3=0,477 , log4=0,602 e / log5=0.699 logaritmos determine o valor de log5 12.

Answer 1

Given that :

log3=0.477 , log4=0.602  and log5=0.699

Now , as you know that

$\log\text{MN}=\log M +\log N$

We have to find the value of

$\log_{5}12$

So,$\log_{5}12$=$\frac{\log12}{ \log5}$             

                         = $\frac{\log 4+\log 3}{\log 5}$

Now Putting the values of log3, log4 and log5 in the above expression

$\log_{5}12=\frac{0.477 +0.602}{0.699}$

                    =1.0079/0.699

                     =1.5436..

                     =1.544 (approx)

So, the value of $\log_{5}12$ is 1.544(approx).