Answer:
The answer:
<W and <Z
<X and <Y
<W and <X
Step-by-step explanation:
Answer:
It is equal to each other
Step-by-step explanation:
![\sqrt{\frac{1}{x^2}} = \frac{1}{x}\\\sqrt[3]{\frac{1}{x^3}} = \frac{1}{x}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B1%7D%7Bx%5E2%7D%7D%20%3D%20%5Cfrac%7B1%7D%7Bx%7D%5C%5C%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7Bx%5E3%7D%7D%20%3D%20%5Cfrac%7B1%7D%7Bx%7D)
Answer: 9πcm²
Step-by-step explanation: area of the square= 36cm²
Therefore, the area of one side= √area = √36 = 6cms
Since the circle is touching the sides of the square, the side of the square = the diameter of the circle
Therefore the radius of the circle= side/2 = 3cm
The formula for the ares of the circle is πr²
π*3*3 = 9πcm²
Calculating
the value of f(x) for the given interval.
For x = -
4, f(x) = f(- 4) = (- 4)^2 + 2 (- 4) + 3 = 11
For x =
6, f(x) = f(6) = (6)^2 + 2 (6) + 3 = 51
Now using
formula for the calculation of average rate of change of f(x) over the given
interval of [- 4, 6];
(f(b) –
f(a)) / b – a = (f(6) – f(- 4)) / 6 – (- 4) = (51 -11) / 10 = 4
<span>So option “E” is
correct.</span>
