Ok sorry for answering i will wait.
For this case we have the following function:
f (t) = -16t2 + 32t + 384
By definition we have to:
The average rate of change:
AVR = (f (t2) - f (t1)) / (t2 - t1)
Where,
For t1 = 4
f (4) = -16 * (4) ^ 2 + 32 * (4) + 384
f (4) = 256
For t2 = 6
f (6) = -16 * (6) ^ 2 + 32 * (6) + 384
f (6) = 0
Substituting values we have:
AVR = (0 - 256) / (6 - 4)
AVR = -128
Answer:
The average rate of change of f (t) from t = 4 seconds to t = 6 seconds is -128 feet per second.
Answer:
4, 6, 1
Step-by-step explanation:
We can solve this problem using a system of equations:
1) a + b + c = 11
2) 2a + 5b + 6c = 44
3) 4a - b = 10
First, we can substitute the value of b from equation #3 into equation #1:
b = 4a - 10
a + (4a - 10) + c = 11
5a - 10 + c = 11
5a + c = 21
c = 21 - 5a
Now, we can plug the values of b and c into equation #2, as b and c are represented in terms of a:
2a + 5(4a - 10) + 6(21 - 5a) = 44
2a + 20a - 50 + 126 - 30a = 44
-8a + 76 = 44
-8a = -32
a = 4
b = 4a - 10 = 4(4) - 10 = 6
c = 21 - 5a = 21 - 5(4) = 1
