The first thing we are going to do for this case is to rewrite the function.
We have then:
y = 3 ^ (2x)
We evaluate the points:
For (1,9):
y = 3 ^ (2 * 1)
y = 3 ^ (2)
y = 9
The point belongs to the function.
For (1/2, 3):
y = 3 ^ (2 * (1/2))
y = 3 ^ (1)
y = 3
The point belongs to the function.
For (-1, -9):
y = 3 ^ (2 * (- 1))
y = 3 ^ (- 2)
y = 1/9
The point does NOT belong to the function.
Answer:
The point (-1, -9) DOES NOT belong to the function.
I do not have a Inspire calculator with me at the time. But I do have the equation you can enter into Solve systems (systems of equations or whatever they call it )
x=touchdowns
y=field goals
x+y=35
7x+3y=193
once you get the results x will still stand for touchdowns and y stands for field goals, and there's your answer.
hoped I helped a little.
Step-by-step explanation:
f(-5)=-5(-5)²+4
f(-5)=5(25)+4
f(-5)=125+4
f(-5)=129
Answer:
3. The solution is the region below the line y = x/2 - 1, above y = -4 and towards left of x = 2. (All bold)
4. The solution is the region above the lines y = -2x/3 -7/3 and y = x/3 - 28/3 and below the line y = -x/6 - 13/3. (All bold)
Step-by-step explanation:
3) 4y ≥ -16
y ≥ -4
2x ≤ 4
x ≤ 2
x-2y ≥ 6
2y ≤ x - 2
y ≤ x/2 - 1
The solution is the region below the line y = x/2 - 1, above y = -4 and towards left of x = 2. (All bold)
4) 2x+3y ≥ -7
3y ≥ -2x -7
y ≥ -2x/3 -7/3
x-3y ≤ 28
3y ≥ x - 28
y ≥ x/3 - 28/3
x+6y ≤ -26
6y ≤ -x - 26
y ≤ -x/6 - 13/3
The solution is the region above the lines y = -2x/3 -7/3 and y = x/3 - 28/3 and below the line y = -x/6 - 13/3. (All bold)
Answer:
<u>point-slope form:</u> y - 0 = ½(x - 3)
Step-by-step explanation:
Given the slope, m = ½, and the x-intercept, (3, 0):
We can substitute these values into the point-slope form:
y - y1 = m(x - x1)
y - 0 = ½(x - 3) ← This is the point-slope form.
If ever you need to transform the point-slope form into its slope-intercept form, y = mx + b:
Distribute ½ into the parenthesis:
y - 0 = ½(x - 3)
y = ½x - 3/2 (this is the slope-intercept form).