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harkovskaia [24]
3 years ago
10

The table and the graph below each show a different relationship between the same two variables, x and y: A table with two colum

ns and 5 rows is shown. The column head for the left column is x, and the column head for the right column is y. The row entries in the table are 4,100 and 5,125 and 6,150 and 7,175. On the right of this table is a graph. The x-axis values are from 0 to 10 in increments of 2 for each grid line. The y-axis values on the graph are from 0 to 300 in increments of 60 for each grid line. A line passing through the ordered pairs 2, 60 and 4, 120 and 6, 180 and 8, 240 is drawn. How much more would the value of y be on the graph than its value in the table when x = 12? 20 30 60 70
Mathematics
1 answer:
Iteru [2.4K]3 years ago
8 0

Answer:

x = 12? 20 30 60 70 thats the answer

Step-by-step explanation:

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Answer:

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Find the length of midsegment YZ in trapezoid ABCD when A(-5,-6) B(-6,-2) C(-4,0) and D(3,2)
Luda [366]

Answer:

Option C

Step-by-step explanation:

Since, Y and Z are the midpoints of sides AB and CD of the given trapezoid.

Segment YZ will the midsegment of trapezoid ABCD.

By the theorem of midsegment,

m(YZ) = \frac{1}{2}(AD+BC)

By using expression for the length of a segment between two points,

Length of a segment = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance between two points A(-5, -6) and D(3, 2),

AD = \sqrt{(3+5)^2+(2+6)^2}

AD = \sqrt{64+64}

AD = \sqrt{128}

AD = 8\sqrt{2}

Distance between B(-6, -2) and C(-4, 0)

BC = \sqrt{(-6+4)^2+(-2-0)^2}

BC = \sqrt{8}

BC = 2\sqrt{2}

Therefore, m(YZ) = \frac{1}{2}(8\sqrt{2}+2\sqrt{2})

                             = \frac{1}{2} (10\sqrt{2})

                             = 5\sqrt{2}

Option C will be the answer.

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Read 2 more answers
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