55 is your answer have a great day
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Answer:
Since the prime factor '3' does not form a triplet , hence the given number is not a perfect cube.
Answer:
x = 4, -10
Step-by-step explanation:
Find the zeros of the equations.
Solve the equation:
x^2 + 6x = 40
Subtract -40 from both sides.
x^2 + 6x - 40 = 0
Factor the equation.
(x - 4)(x + 10)
Solve for x with the given information by equaling it to 0.
x - 4 = 0
Add 4 to both sides
x = 4
x + 10 = 0
Subtract 10 from both sides
x = -10
This means that our x values are:
x = 4, -10
Compute asymptotes of<span> a function or curve and compute </span>vertical<span>, </span>horizontal<span>, oblique, ... </span>asymptotes x<span>^2 + </span>y^3<span> = (x y)^2 ... oblique </span>asymptotes<span> (4x^</span>3<span> + </span>1)/(x<span>^2 - </span>1<span>).</span>
