To solve this we must isolate x which involves having the variables on one side and the numbers on the other.
First add 2m to both sides
<em>3m+7/2=-2m+5/2</em>
<em>5m+7/2=5/2</em>
Then we subtract 7/2 from both sides
<em>5m+7/2=5/2</em>
<em>5m=-1</em>
Finally we divide both sides by 5
<em>5m/5=-1/5</em>
<em>Our final answer is -1/5</em>
<em>So the answer is B</em>
Hope this helps!
B because it is moved but doesn’t change size
Answer:
angle 6 and angle 2 are corresponding
A= B+C
As given, A+B+C = 50000 seats
A+(B+C) = 50000
2A = 50000
A= 25000 seats
Now section A sells seats at $30 each
So, 
Now, B+C = 25000
B = 25000-C
B sells at $24 and C sells at $18
So, 24B+18C = 538800
Now as section A incurs an amount of $750000 from booking, so B and C will incur 1288800-750000 = 538800 where $1288800 is the total booking amount.
24B+18C = 538800
6C = 61200
C = 10200
Now, B = 25000-C
B = 25000 - 10200 = 14800
Hence, section A has 25000 seats
Section B has 14800 seats
Section C has 10200 seats
Answer:
100
Step-by-step explanation:
Given that 2 ap's have same common difference
given that their 100th terms difference is 100
let the first no. of first series be a1 and second series be a2
then, a(1)100 - a(2)100=100 ---- 1
for 1st series ---- a100=a1+99d
2nd series ---- a100 = a2+99d
keep these values in (1)
then,
a1+99d - (a2+99d) = 100
a1+99d-a2-99d=100
therefore, a1-a2 =100 ------------------------------------------- 2
then the difference between their 1000th terms is
for 1st series --- a1000 = a1+999d
for 2nd series --- a1000 = a2+999d
their 100th terms difference is
a(1)1000-a(2)1000
a1+999d-(a2+999d)
a1+999d-a2-999d
therefore we get the value a1-a2
from (2) a1-a2 = 100
therefore the difference between their 1000th terms is 100
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