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3 years ago

5

A small town wants to compare the number of students enrolled in public and private schools. The polynomials below show the enro

llment for each: Public School: –19c2 + 980c + 48,989 Private School: 40c + 4046

1 answer:

Zolol [24]3 years ago

6 0

Answer:

-19c2

Step-by-step explanation:

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Solve the following inequality for x, then describe what the graph would look like.

Alex17521 [72]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

Inequality Form:

x≤−3

Interval Notation: ( − ∞ , − 3 ]

4 0

3 years ago

The planets move around the sun in elliptical orbits with the sun at one focus. The point in the orbit at which the planet is cl

gladu [14]

Consider the attached ellipse. Let the sun be at the right focus. Then perihelion is at right vertex on the x-axis and aphelion is at the left vertex on the x-axis.

The distances:

from perihelion to the sun in terms of ellipse is a-c;
from aphelion to the sun in terms of ellipse is a+c.

Then

$\left\{\begin{array}{l}a-c=741,000,000\\a+c=817,000,000\end{array}\right.$

Add these two equations:

$2a=1,558,000,000 \\ \\a=779,000,000$

and subtract first equation from the second:

$2c=76,000,000 \\ \\c=38,000,000.$

Note that $b=\sqrt{a^2-c^2},$ thus

$b=\sqrt{779,000,000^2-38,000,000^2}=\sqrt{605,397,000,000,000,000}.$

The equation for the planet's orbit is

$\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1\Rightarrow \dfrac{x^2}{606,841,000,000,000,000}+\dfrac{y^2}{605,397,000,000,000,000}=1.$

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3 years ago

Which correlation coefficient corresponds to the best-fit line that most closely models its set of data?

Deffense [45]

The answer for this question is c

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3 years ago

Read 2 more answers

The age of the Hawaiian islands gets older as you move from east to west. If the half-life of K-40 is 1.3 billion years, approxi

Mumz [18]

Answer:

$t \approx 750550.12\,yr$

Step-by-step explanation:

The time constant of the isotope is:

$\tau = \frac{1.3\times 10^{9}\,yr}{\ln 2}$

$\tau \approx 1.876 \times 10^{9}\,yr$

The decay of the isotope is described by the following model:

$\frac{m}{m_{o}} = e^{-\frac{t}{\tau} }$

Now, the time is cleared in the equation:

$t = -\tau \cdot \ln \frac{m}{m_{o}}$

$t = - (1.876\times 10^{9}\,yr)\cdot \ln 0.9996$

$t \approx 750550.12\,yr$

5 0

3 years ago

How do I solve this?

Anni [7]

I hope this helps you

4^3/3.x^2/3.y^3/3

4.y.x^2/3

3 0

3 years ago