Add And Simplify 5/9 + 7/9 = 7 1/2 + 3 3/8 = 4 4/15 +1/5 = 1/7+3/7 =

I don’t know how to solve this.

aev [14]

Answer:

24

Step-by-step explanation:

put 2 over 3 and then simplify it then add the answer with 24

8 0

3 years ago

I need help ASAP !!!

lbvjy [14]

The answer is (x,y) —> (y,-x)

8 0

4 years ago

2. A carpenter wants to cut a wood board that is feet long

belka [17]

Answer:

2 whole pieces

5/24 feet left

Step-by-step explanation:

divide 5/6 by 5/16 = 2 2/3 pieces

so there are 2 whole pieces and 2/3 small piece.

The 2/3 small short equals to 5/16 x 2/3 = 5/24 ft

8 0

3 years ago

Someone claims that the breaking strength of their climbing rope is 2,000 psi, with a standard deviation of 10 psi. We think the

denpristay [2]

Answer:

The sample size must be greater than 37 if we want to reject the null hypothesis.

Step-by-step explanation:

We are given that someone claims that the breaking strength of their climbing rope is 2,000 psi, with a standard deviation of 10 psi.

Also, we are given a level of significance of 5%.

Let $\mu$ = mean breaking strength of their climbing rope

SO, Null Hypothesis, $H_0$ : $\mu$ = 2,000 psi {means that the mean breaking strength of their climbing rope is 2,000 psi}

Alternate Hypothesis, $H_A$ : $\mu$ < 2,000 psi {means that the mean breaking strength of their climbing rope is lower than 2,000 psi}

Now, the test statistics that we will use here is One-sample z-test statistics as we know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = ample mean strength = 1,997.2956 psi

$\sigma$ = population standard devaition = 10 psi

n = sample size

Now, at the 5% level of significance, the z table gives a critical value of -1.645 for the left-tailed test.

So, to reject our null hypothesis our test statistics must be less than -1.645 as only then we have sufficient evidence to reject our null hypothesis.

SO, T.S. < -1.645 {then reject null hypothesis}

$\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < -1.645$

$\frac{1,997.2956-2,000}{\frac{10}{\sqrt{n} } } < -1.645$

$(\frac{1,997.2956-2,000}{10}) \times {\sqrt{n} } } < -1.645$

$-0.27044 \times \sqrt{n}< -1.645$

$\sqrt{n}> \frac{-1.645}{-0.27044}$

$\sqrt{n}>6.083$

n > 36.99 ≈ 37.

SO, the sample size must be greater than 37 if we want to reject the null hypothesis.

7 0

4 years ago

SCIENCE CENTER The expression 20a + 13c is the cost (in dollars) for a adults and c students to enter a science center. A. How m

Marianna [84]

Answer:

Step-by-step explanation:

A. It costs $20 per adult. If this is a cost fuction, which it is because the wording is "the cost (in dollars) for a adults and c students", adult is a, the cost for 1 adult, 1a, is 20. That relates the number of adults to the cost of 1 adult.

It costs $13 per student. Again, this is a cost function, so since student is c, the cost for 1 student, 1c, is 13. That relates the number of students to the cost of 1 student.

B. The total cost for 4 adult and 24 students looks like this:

20(4) + 13(24) which is 80 + 312 = $392

C. If you have 3 adults and 3 students in your group, the cost is 20(3) + 13(3) which is $99. If you double the number of each, let's see if the cost doubles. We will "up" the numbers to 6 each. 20(6) + 13(6) = $198. Is $198 the double of $99. Yes it is. Let's do it again to check. Let's double the 6.

20(12) + 13(12) = $396, and $198 doubled does in fact equal $396. So there you go!

5 0

3 years ago