To answer this, you will use the area of 900 square yards to determine the distances between the bases. Each side of the square is 30 yards, so it will be 30 yards from 1st to home and from 1st to 2nd.
The distance from home to 2nd is a diagonal in the square (the hypotenuse).
You will use the Pythagorean Theorem to find this distance.
a^2 + b^2 = c^2
30^2 + 30 ^2 = c^2
900 + 900 + c^2
1800 = c^2
The square root of 1800 is approximately 42.4 yards.
The ball travels approximately 42.4 yards.
Answer:
1/2 mile/1/5 hour = 5/2 mph = 2 1/2 mph
Step-by-step explanation:
Answer:
what do you need help with?
Step-by-step explanation:
A graph with a dotted line running through the points (-4, 0) and (0, 6) shaded above the origin.
Answer:
BC = 3(EF)
Step-by-step explanation:
The question stated that AC is 3 times the length of DF.
