9514 1404 393
Answer:
- f(x) = x
- g(x) = -2x+1
- f(x) -(-g(x)) = -x+1
- f(x) +g(x) = -x+1
- f(x)-(-g(x)) = (f+g)(x) is true for all functions f and g, linear or not
Step-by-step explanation:
We can define a couple of linear functions as ...
f(x) = x
g(x) = -2x+1
Then the reflected function -g(x) is ...
-g(x) = -(-2x +1) = 2x -1
And the difference from f(x) is ...
f(x) -(-g(x)) = x -(2x -1) = -x +1 . . . . f(x) -(-g(x))
We want to compare that to the sum of the functions:
f(x) +g(x) = x +(-2x +1) = -x +1 . . . . f(x) +g(x)
The two versions of the function expression have the same value.
These results are <em>a property of addition</em>, so do not depend on the nature of f(x) or g(x). They will hold for every function.
Answer:
0.075
Step-by-step explanation:
You can do it the bus way method(on paper')
or use a calculator
hope this helped have a great day
Answer:
she has 6 quarters and 2 nickels
Step-by-step explanation:
IDK which of the answer chioces that is tho they were confusing me
<u>Answer-</u>
<em>Equation 1</em><em> is the equation which represents the graph.</em>
<u>Solution-</u>
From the graph it can be noticed that, the function is a hyperbola. It is a rectangular hyperbola.
The general form of rectangular hyperbola is,
Where c is a constant.
Equation 1 represents a function of rectangular hyperbola, with vertical asymptote as x=-2 .
Equation 2 represents an exponential function.
Equation 2 represents an cubic function.
Equation 2 represents logarithmic function.
Therefore, equation 1 is the equation which represents the graph.
8). x=(-1+√22)/2 , x=(-1-√22)/3
9). x=(1+√5)/2 , x=(1-√5)/2
10). x=3 , 1/4
11). x=1/3 , -1
12). x=2+2√3 , 2-2√3
