<u>Note: The only way to solve this problem is by adjusting the fees to $3.50 and $7.50.</u>
Answer:
<em>1300 children attended the basketball game</em>
Step-by-step explanation:
System of Equations
Let's call:
x = number of children attending the basketball game
y = number of adults attending the basketball game
On a certain night, 1500 people enter the game, thus:
x + y = 1500 [1]
Since each admission fee for children cost $3.50 and $7.50 for adults and it was collected $6050, thus:
3.50x + 7.50y = 6050 [2]
From [1]:
y = 1500 - x
Substituting in [2]:
3.50x + 7.50(1500 - x) = 6050
Operating:
3.50x + 11250 - 7.50 = 6050
-4x = 6050 - 11250
Solving:
x = 1300
1300 children attended the basketball game
The median is 38.5
The lower quartile is 29
There is an outlier (154)
The upper quartile is 70
and
The interquartile range is 70 - 29 = 41
Answer:
The correct answer is (x-y)
Step-by-step explanation:
x^2-xy
x(x-y)
Answer:
answer is 5.3 cuz I am smart I learned this so I'm here to help
Find all the prime factors of the three numbers. pick up the common factors, ONCE, then pick up the non-common factors one by one, multiply the factors, the product is the least common factor.
example: the least common multiple of 6, 8, and 15
6=2*3
8=2*2*2
15=3*5
Note: do not write 8 into 4*2, because 4 is not a prime number. you have to break the number down to prime factors only.
Notice that 6 and 8 have a common factor 2, so pick up the 2;
6 and 15 have a common factor of 3, so pick up the 3.
those are the only two shared factors, so 2×3
now pick up whatever is not shared:
the two 2s for 8 and the 5 for 15 is not shared, add 2, 2, and 5 to the multiplication: 2×3×2×2×5=120
120 is the least common multiples of 6,8, and 15
this is basically how it is done. I believe you can explain better in your own words.
