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krek1111 [17]
3 years ago
15

PLEASE HELP!!!! Graph f(x) =-0.25x+4 , just tell me the points. please

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
5 0
What. that makes so sense
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which of the following correctly describes the end behavior of the polynomial function f(x)=-x^3+x^2-4x+2
SIZIF [17.4K]

Answer:

The left end goes up and the right end goes down.

Step-by-step explanation:

Lets solve the function first and then find out the end behavior of the polynomial:

The given function is  f(x)=-x^3+x^2-4x+2

First step is: Identify the degree of the polynomial. For this we have to  find out the variable with the largest exponent.

The variable with the largest exponent in the given function is -x³

The degree of the polynomial is the largest exponent on the variable.

3 is the degree of the polynomial.

Since the degree is Odd, the ends of the function will point in the opposite direction.

Now find out the leading coefficient of the polynomial which is -1.

Since the leading coefficient is negative the graph falls to the right.

To find the behavior we have to use the degree of the polynomial as well as the sign of leading coefficient.

If it is ODD and NEGATIVE then the the left end goes up and the right end goes down.

Therefore the end behavior of the given function will be described as "the the left end goes up and the right end goes down"....

6 0
3 years ago
The answer to 5 x 6 + 6
Reika [66]
36


Anyways thank for points
5 0
3 years ago
Read 2 more answers
A group issimpleif it has no nontrivial proper normal subgroups. LetGbe a simple group of order168. How many elements of order 7
stepladder [879]

Answer:

6*8=48 groups with elements of order 7

Step-by-step explanation:

For this case the first step is discompose the number 168 in factors like this:

168 = 8*3*7= 2^3 *3*7

And for this case we can use the Sylow theorems, given by:

Let G a group of order p^{\alpha} m  where p is a prime number, with m\leq 1 and p not divide m then:

1) Syl (G) \neq \emptyset

2) All sylow p subgroups are conjugate in G

3) Any p subgroup of G is contained in a Sylow p subgroup

4) n(G) =1 mod p

Using these theorems we can see that 7 = 1 (mod7)

By the theorem we can't have on one Sylow 7 subgroup so then we need to have 8 of them.

Every each 2 subgroups intersect in a subgroup with a order that divides 7. And analyzing the intersection we can see that we can have 6 of these subgroups.

So then based on the information we can have 6*8=48 groups with elements of order 7 in G of size 168

3 0
3 years ago
7.
Cloud [144]

Answer:

não sei não falo seu idioma

7 0
4 years ago
X-3/18=12/9<br> what is the answer? It is proportions.
olga nikolaevna [1]

Answer:

x=3/2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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