(8x 2 −15x)−(x 2 −27x)=ax 2 +bxleft parenthesis, 8, x, squared, minus, 15, x, right parenthesis, minus, left parenthesis, x, squ
quester [9]
Answer:
<h2>5</h2>
Step-by-step explanation:
Given the expression (8x² −15x)−(x² −27x) = ax² +bx, we are to determine the value of b-a. Before we determine the vwlue of b-a, we need to first calculate for the value of a and b from the given expression.
On expanding the left hand side of the expression we have;
= (8x² −15x)−(x² −27x)
Open the paranthesis
= 8x² −15x−x²+27x
collect the like terms
= 8x²−x²+27x −15x
= 7x²+12x
Comparing the resulting expression with ax²+bx
7x²+12x = ax²+bx
7x² = ax²
a = 7
Also;
12x = bx
b =12
The value of b - a = 12 - 7
b -a = 5
Hence the value of b-a is equivalent to 5
The correct answer is x= -1. Hope this helps!!
Hello!
To find the circumference of a circle you do
where r is the radius of the circle
So we do 2
Then we substitute pi for 3.14
2 * 3.14 * 72 = 452.16 yds
Then we multiply this by 5 since he runs 5 laps
Which gives us the answer of 2260.8 yds
Hope this helps!
Answer:
hello :
the area is : A= w ×l ... w : the width l : the length
A = 323 l = 19 w ?
l = A/w
l = 323/ 19
l = 17 feet
