The answer is C.54.45.43.54
Answer:
Table for Area codes are not missing;
See Attachment for area codes and major city I used
This program will be implemented using c++ programming language.
// Comments are used for explanatory purposes
// Program starts here
#include <iostream>
using namespace std;
int main( )
{
// Declare Variable area_code
int area_code;
// Prompt response from user
cout<<Enter your area code: ";
cin<<"area_code;
// Start switch statement
switch (area_code) {
// Major city Albany has 1 area code: 229...
case 229:
cout<<"Albany\n";
break;
// Major city Atlanta has 4 area codes: 404, 470 678 and 770
case 404:
case 470:
case 678:
case 770:
cout<<"Atlanta\n";
break;
//Major city Columbus has 2 area code:706 and 762...
case 706:
case 762:
cout<<"Columbus\n";
break;
//Major city Macon has 1 area code: 478...
case 478:
cout<<"Macon\n";
break;
//Major city Savannah has 1 area code: 912..
case 912:
cout<<"Savannah\n";
break;
default:
cout<<"Area code not recognized\n";
}
return 0;
}
// End of Program
The syntax used for the above program is; om
Answer:
void printC()
{
int i, j;
for (i = 0; i < 4; i++) //i indicate row number. Here we have 5 rows
{
printf("C"); //print C for every row
for (j = 0; j < 6; j++) //j indicate column number. Here we have 7 Rows
{
if (i == 0 || i == 4) //For first and last row
printf("C"); //print 'CCCCCCC'
else if (i = 1|| i= 3) //for Second forth row
printf("C + +"); //print 'C + +'
else if (i = 2) For second row
printf("C +++++"); //print 'C +++++'
else
continue; //to jump to next iteration
}
printf("\n"); // print in next line
}
}
Alice has twice as many pencils as Cara. Leon has three more pencils than Alice. The three children have a total of 58 pencils.
<h3>
What are the no. of pencils?</h3>
The no. of pencils are there totally as the 11.
Read more about the basic maths:
brainly.com/question/19493296
#SPJ1
Answer:
i dont know sorry but answer above lol
Explanation: