Ask question

Ask question

All categories

3 years ago

8

Solving for the Missing Proportions version 1 2 = 32 I don’t get it

1 answer:

stich3 [128]3 years ago

4 0

Answer:

Step-by-step explanation:

2 x ? = 32 = 2x16=32

You might be interested in

Wrestling coach is entering his team in a tournament there is a $75 fee for each team entered plus a five dollar fee for each wr

Olegator [25]

Answer:

188 wrestlers

Step-by-step explanation:

Given

$F =5w + 75$

$F = 1013$

Required

Determine the number of wrestlers (w)

We have:

$F =5w + 75$

Substitute: $F = 1013$

$1013 = 5w + 75$

Collect like terms

$5w = 1013 - 75$

$5w = 938$

Divide both sides by 5

$w = 187.6$

Round up to get the number of wrestlers

$w = 188$

5 0

2 years ago

Use the graph of the quadratic function to identify the solutions when y = 0.

ludmilkaskok [199]

The answer is A I had this on my test in math class earlier on my math test

3 0

3 years ago

Write the whole number in the expanded form

baherus [9]

87,602 in expanded form is 80,000+7,000+600+2

8 0

3 years ago

Read 2 more answers

2.The number of grams A of a certain radioactive substance present at time, in yearsfrom the present, t is given by the formulaA

professor190 [17]

Answer:

Given that,

The number of grams A of a certain radioactive substance present at time, in years

from the present, t is given by the formula

$A=45e^{-0.0045(t)}$

a) To find the initial amount of this substance

At t=0, we get

$A=45e^{-0.0045(0)}$ $A=45e^0$

We know that e^0=1 ( anything to the power zero is 1)

we get,

$A=45$

The initial amount of the substance is 45 grams

b)To find thehalf-life of this substance

To find t when the substance becames half the amount.

A=45/2

Substitute this we get,

$\frac{45}{2}=45e^{-0.0045(t)}$

$\frac{1}{2}=e^{-0.0045(t)}$

Taking natural logarithm on both sides we get,

$\ln (\frac{1}{2})=-0.0045(t)^{}$ $(-1)\ln (\frac{1}{2})=0.0045(t)$ $\ln (\frac{1}{2})^{-1}=0.0045(t)$ $\ln (2)=0.0045(t)$ $0.6931=0.0045(t)$ $t=\frac{0.6931}{0.0045}$ $t=154.02$

Half-life of this substance is 154.02

c) To find the amount of substance will be present around in 2500 years

Put t=2500

we get,

$A=45e^{-0.0045(2500)}$ $A=45e^{-11.25}$ $A=45\times0.000013=0.000585$ $A=0.000585$

The amount of substance will be present around in 2500 years is 0.000585 grams

4 0

6 months ago

In a certain community, 36 percent of the families own a dog and 22 percent of the families that own a dog also own a cat. In ad

zysi [14]

Answer: a) 0.0792 b) 0.264

Step-by-step explanation:

Let Event D = Families own a dog .

Event C = families own a cat .

Given : Probability that families own a dog : P(D)=0.36

Probability that families own a dog also own a cat : P(C|D)=0.22

Probability that families own a cat : P(C)= 0.30

a) Formula to find conditional probability :

$P(B|A)=\dfrac{P(A\cap B)}{P(A)}\\\\\Rightarrow P(A\cap B)=P(B|A)\times P(A)$ (1)

Similarly ,

$P(C\cap D)=P(C|D)\times P(D)\\\\=0.22\times0.36=0.0792$

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792

b) Again, using (2)

$P(D|C)=\dfrac{P(C\cap D)}{P(C)}\\\\=\dfrac{0.0792}{0.30}=0.264$

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264

5 0

2 years ago