A basket contains the following pieces of fruit: 3 apples, 2 oranges, 2 bananas, 2 pears, and 5 peaches. Jack picks a fruit at r
andom and does not replace it. Then Bethany picks a fruit at random. What is the probability that Jack gets a peach and Bethany gets an orange?
2 answers:
Hello!
You have to find the probabilities of them happening separately
To do this you do the amount of favorable outcomes over the total amount of outcomes
3 + 2 + 2 + 2 + 5 = 14 total fruit
The chance of Jack getting a peach is 5 / 14
The chance of Bethany getting an orange is 2 / 13 because Jack did not put the fruit back in so their is one less to choose from
You multiply the two probabilities to find the probability of them happening in a row
5/14 * 2/13 = 5/91
The answer is 5/91
Hope this helps!
5/14 × 2/13 = 10/182
simplify by 2
10/182 ÷ 2/2
5/91
5 over 91
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