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padilas [110]
3 years ago
14

Tanisha and Neal are simplifying the expression (StartFraction (x Superscript 4 Baseline) (y Superscript negative 5 Baseline) Ov

er 3 (x squared) (y Superscript negative 3 Baseline) EndFraction) Superscript 4. They each began the same way.
Tanisha’s Work
Neal’s Work
(StartFraction (x Superscript 4 Baseline) (y Superscript negative 5 Baseline) Over 3 (x squared) (y Superscript negative 3 Baseline) EndFraction) Superscript 4 = (StartFraction (x squared) (y Superscript negative 2 Baseline) Over 3 EndFraction) Superscript 4
(StartFraction (x Superscript 4 Baseline) (y Superscript negative 5 Baseline) Over 3 (x squared) (y Superscript negative 3 Baseline) EndFraction) Superscript 4 = StartFraction (x Superscript 16 Baseline) (y Superscript negative 20 Baseline) Over (3 Superscript 4 Baseline (x Superscript 8 Baseline) (y Superscript negative 12 Baseline) EndFraction


Which statements are true about each person’s work? Check all that apply.
Mathematics
2 answers:
Alex787 [66]3 years ago
3 0

Answer:

You didn't the statements from which you like to know which ones are true.

But it is discovered that Neal's work is correct to the point where he stopped, but Tanisha's work has a mistake in it.

Step-by-step explanation:

Tanisha and Neal want to simplify the expression :

(x^4 y^(-5)/3x²y^(-3))^4

Tanisha's approach

(x^4 y^(-5)/3x²y^(-3))^4

= (x²y^(-2)/3^4)^4

Neil's approach.

(x^4 y^(-5)/3x²y^(-3))^4

= x^(16) y^(-20)/3^4(x^8 y^(-12))

Simplifying the expression using Tanisha's approach.

(x^4 y^(-5)/3x²y^(-3))^4

= (x²y^(-2)/3)^4

= x^(2×4) y^(-2×4)/3^4

= x^8 y^(-8)/3^4

= 3^(-4) (x/y)^8

Solving using Neal's approach.

(x^4 y^(-5)/3x²y^(-3))^4

= (x^4 y^(-5))^4/(3x²y^(-3))^4

= x^(4×4) y^(-5×4) / (3^4 x^(2×4) y^(-3×4)

= x^16 y^(-20)/ 3^4 x^8 y^(-12)

= x^(16-8) y^(-20+12) 3^(0-4)

= x^8 y^(-8) 3^(-4)

= x^8/3^4 y^8

= 3^(-4) (x/y)^8

From this, we can say that straightaway Neal's is on the line. His approach is correct, so is his work.

Tanisha's approach is acceptable too, but the results in her work is questionable. There should be

(x²y^(-2)/3)^4 not (x²y^(-2)/3^4)^4, it changes everything.

ra1l [238]3 years ago
3 0

Answer:

It will be 2,3,4 and 6.

Step-by-step explanation:

took the test and they came out that these where the correct. Plus when looking at the work you can tell that they both are on tract and are correct. and the next steps needed to be taken.

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Which of the following expressions are equivalent to 312?
lord [1]

Answer:

3(4+3^2)×8

Step-by-step explanation:

Evaluate the power

3(4+9)×8

Add the numbers 3×13×8

Calcuate the product and it will be 312

So the expression 3×(4+3^2)×8 are equivalent to 312

Hope this helpsʕ•ᴥ•ʔ

4 0
3 years ago
Claire has $210 to spend on clothes. She wants to buy a pair of shorts and some shirts. The cost of a pair of shorts is $25, and
Komok [63]

Answer:

discount of 50% on one shirt, which inequality can be used to find the maximum number of shirts, n, that she can buy?

Step-by-step explanation:

has $210 to spend on clothes. She wants to buy a pair of shorts and some shirts. The cost of a pair of shorts is $25, and the cost of a shirt is $40. If she gets a discount of 50% on one shirt, which inequality can be used to find the maximum number of shirts, n, that she can buy?

3 0
4 years ago
Help your girl out out!
Sliva [168]
The answer would be 10.8

9/5=x/6
Cross multiply
5x=54
Divide by 5
x=10.8
4 0
3 years ago
Read 2 more answers
What is the value of [-12]
algol13

Answer:

12.

Step-by-step explanation:


7 0
4 years ago
The dot plot represents the length of practice time in minutes for the math competition. Explain how the outlier of the data aff
lidiya [134]

Using statistical concepts, it is found that:

  • The mean practice time decreases because of the outlier.
  • The median practice time does not change because of the outlier.
  • The range increases because of the oulier.

<h3>What are the mean, the median and the range of a data-set?</h3>

  • The mean is the sum of all observations divided by the number of observations.
  • The median is the middle value, the value that separates the upper 50% from the bottom 50%.
  • The range is the difference between the largest value and the smallest.

From their concepts above, we have that the mean and the range are influenced by outliers.

In this problem, the outlier is at the low end, of 15, hence:

  • The mean practice time decreases because of the outlier.
  • The median practice time does not change because of the outlier.
  • The range increases because of the oulier.

More can be learned about statistical concepts at brainly.com/question/24732674

#SPJ1

3 0
2 years ago
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