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NISA [10]
3 years ago
15

Can you solve 13 and 14 I’ll make you brilliant ASAP

Mathematics
1 answer:
jenyasd209 [6]3 years ago
5 0

Answer:

  • 13. t = 5
  • 14. 135 min

Step-by-step explanation:

13...........

f(t) = 2^(t/3)

f(t) = 32

  • 2^(t/3) = 32
  • 2^(t/3) = 2^5
  • t/3 = 5
  • t = 5*3
  • t = 15

14............

b = 100(2^t)

b= 51200

  • 100(2^t)= 51200
  • 2^t= 512
  • 2^t= 2^9
  • t = 9

9 periods of 15 min:

  • 9*15 = 135 min
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well, this is just a matter of simple unit conversion, so let's recall that one revolution on a circle is just one-go-around, radians wise that'll be 2π, and we also know that 1 minute has 60 seconds, let's use those values for our product.

\cfrac{300~~\begin{matrix} r \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{~~\begin{matrix} min \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }\cdot \cfrac{2\pi ~rad}{~~\begin{matrix} r \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }\cdot \cfrac{~~\begin{matrix} min \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{60secs}\implies \cfrac{(300)(2\pi )rad}{60secs}\implies 10\pi ~\frac{rad}{secs}\approx 31.42~\frac{rad}{secs}

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2 years ago
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Step-by-step explanation:

6 0
3 years ago
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