Answer: 29.28 years
Explanation:
From Kepler's third law the square of orbital period of revolving celestial body is proportional to the cube of semi -major axis from the body it is revolving about.
P² =A³
Where, P is the orbital period in years and A is the semi-major axis in AU (Astronomical units)
It is given that, For Saturn, A = 9.5 AU. We need to find P
⇒P² = (9.5 AU)³
⇒P² = 857.38
⇒P = 29.28 years
Thus, the orbital period of Jupiter is 29.28 years around the Sun.
Answer:
4:3
Step-by-step explanation:
divide both sides by 5 giving you 4:3
Answer:
D
Step-by-step explanation:
Answer:
11, 13 and 15.
Step-by-step explanation:
Let's say that the odd number is "x". If x is for example 15, then the next ODD number would be 15+2=17 and the one after that would be 15+2+2=15+4=19.
Applying that here, we get:
Odd number* the next odd number*the next odd number=2145
x*(x+2)*(x+4)=2145
x*(x^2+4x+2x+8)=2145
x^3+6x^2+8x=2145
By solving the polynomial, you get x=11.
Which makes our three numbers: 11, 13 and 15.
11*13*15=2145. The answer checks.
