Answer:
-9, 15
Step-by-step explanation:
Subtract 7 and multiply by 4
1/4 |2x-6| +7 = 13
1/4 |2x -6| = 6
|2x -6| = 24
2x -6 = ± 24
2x = 6 ±24
x = 3 ±12
x = -9, 15
_____
For graphing purposes, it is often convenient to rewrite the equation so the solutions are where the function is zero. Here, we can do that by subtracting 13 from the equation.
(1/4 |2x -6| +7) -13 = 0
Answer:
sooo i think, it is
Step-by-step explanation: it screen shot cause i worked it out on my computer !
Answer:
41.94% probability that a worker earned between $400 and $500.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a worker earned between $400 and $500?
This is the pvalue of Z when X = 500 subtracted by the pvalue of Z when X = 400. So
X = 500



has a pvalue of 0.7422
X = 400



has a pvalue of 0.3228
So there is a 0.7422 - 0.3228 = 0.4194 = 41.94% probability that a worker earned between $400 and $500.
Step-by-step explanation:
according to arrow the weight is 1400 g.
we know,
1 kg = 1000 g
so,
1 g = 1/1000 kg
so,
1400/1000 = 1.4 kg ans
hope this answer helps you dear!
Mary is x years old
when we write the expression for her age which represents 12 years from now, it means we have to add 12 years in the age of Mary, and she is x years old now
so the expression will be:
x+12
and the expression which represents her age two years ago from now when she is x years old is:
x-2
if we know the x, we can calculate easily her age for above two expressions.