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3 years ago

Need help with the problem in the photo.

Mathematics

2 answers:

mr_godi [17]3 years ago

4 0

Answer:

B. 3x -2y = 10

Step-by-step explanation:

The given line rises three units for each two units of run to the right. Hence its slope is 3/2. A parallel line will also have a slope of 3/2.

Of the equations we can see, selection B has a slope of 3/2. It can be rewritten in slope-intercept form as ...

3x -10 = 2y . . . . . add 2y-10 to isolate the y-term; next divide by 2.

y = 3/2x -5 . . . . . the coefficient of x is the slope

Lapatulllka [165]3 years ago

3 0

Answer:

B. 3x -2y = 10

Step-by-step explanation:

The given line rises three units for each two units of run to the right. Hence its slope is 3/2. A parallel line will also have a slope of 3/2.

Of the equations we can see, selection B has a slope of 3/2. It can be rewritten in slope-intercept form as ...

3x -10 = 2y . . . . . add 2y-10 to isolate the y-term; next divide by 2.

y = 3/2x -5 . . . . . the coefficient of x is the slope

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Find a and b so that f(x) = x^3 + ax^2 + b will have a critical point at (2,3).

Digiron [165]

Using the critical point concept, it is found that a = -3 and b = 7.

<h3>What are the critical points of a function?</h3>

The critical points of a function are the values of x for which:

$f^{\prime}(x) = 0$

In this problem, the function is:

$f(x) = x^3 + ax^2 + b$

Hence, the derivative is:

$f^{\prime}(x) = 3x^2 + 2ax$

Then:

$f^{\prime}(x) = 0$

$3x^2 + 2ax = 0$

$x(3x + 2a) = 0$

$x = 0$

$3x + 2a = 0$

$3x = -2a$

$x = -\frac{2a}{3}$

Since the critical point is at x = 2, we have that:

$-\frac{2a}{3} = 2$

$-2a = 6$

$2a = -6$

$a = -3$

Then:

$f(x) = x^3 - 3x^2 + b$

Critical point at (2,3) means that when $x = 2, y = 3$ , then:

$3 = 2^3 - 3(2)^2 + b$

$8 - 12 + b = 3$

$b = 7$

You can learn more about the critical point concept at brainly.com/question/2256078

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2 years ago