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Paladinen [302]

3 years ago

6

Incorrect, 4.3.37

2 answers:

Andreas93 [3]3 years ago

5 0

The number of ways is given directly using the formula:
$C_{10}^4\times C_6^3\\\text{wherein }C_n^k=\dfrac{n!}{k!(n-k)!}.\text{ Using the formula we get:}\\C_{10}^4\times C_6^3=\dfrac{10!}{4!(10-4)!}\dfrac{6!}{3!(6-3)!}\\=4200$
(Use a calculator in order to reach the above result.)
So tête number of ways is 4200.

Jlenok [28]3 years ago

5 0

2 with a remainder of one man

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