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Paladinen [302]
3 years ago
6

Incorrect, 4.3.37

Mathematics
2 answers:
Andreas93 [3]3 years ago
5 0
The number of ways is given directly using the formula:
C_{10}^4\times C_6^3\\\text{wherein }C_n^k=\dfrac{n!}{k!(n-k)!}.\text{ Using the formula we get:}\\C_{10}^4\times C_6^3=\dfrac{10!}{4!(10-4)!}\dfrac{6!}{3!(6-3)!}\\=4200
(Use a calculator in order to reach the above result.)
So tête number of ways is 4200.
Jlenok [28]3 years ago
5 0
2 with a remainder of one man
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