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Paladinen [302]
3 years ago
6

Incorrect, 4.3.37

Mathematics
2 answers:
Andreas93 [3]3 years ago
5 0
The number of ways is given directly using the formula:
C_{10}^4\times C_6^3\\\text{wherein }C_n^k=\dfrac{n!}{k!(n-k)!}.\text{ Using the formula we get:}\\C_{10}^4\times C_6^3=\dfrac{10!}{4!(10-4)!}\dfrac{6!}{3!(6-3)!}\\=4200
(Use a calculator in order to reach the above result.)
So tête number of ways is 4200.
Jlenok [28]3 years ago
5 0
2 with a remainder of one man
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Solve Sine inverse x +sine inverse 2x = π/3 <br> Please solve it faster..
LuckyWell [14K]
Arcsin x + arcsin 2x = π/3

arcsin 2x =  π/3 - arcsin x

sin[arcsin 2x] = sin[π/3 - arcsin x] (remember the left side is like sin(a-b)

2x = sinπ/3 cos(arcsin x)-cosπ/3 sin(arc sinx)

2x = √3/2 . cos(arcsin x) - (1/2)x)

but cos(arcsin x) = √(1-x²)===>2x = √3/2 .√(1-x²)  - (1/2)x)

Reduce to same denominator:

(4x) = √3 .√(1-x²)  - (x)===>5x = √3 .√(1-x²)

Square both sides==> 25x²=3(1-x²)

28 x² = 3 & x² = 3/28 &  x =√(3/28)



3 0
3 years ago
6^3-4^2+17divide(x-4)
mr Goodwill [35]

Answer:

-54.25

Step-by-step explanation:

Just do it step by step and youll get the answer

5 0
2 years ago
Anwser: <br><br> (1-4-6+56)×6-8-3
baherus [9]

Answer:

PEMDAS, do multiplication first then, adddition, then subtraction

Step-by-step explanation:

7 0
3 years ago
Can someone help me out with this?? It’s due soon...
Inessa05 [86]
1. 1.25

2. 0.85

3. 0.2

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5 0
3 years ago
When Carson runs the 400 meter dash, his finishing times are normally distributed with a mean of 63 seconds and a standard devia
Gnom [1K]

Answer: in 95% of races, his finishing time will be between 62 and 64 seconds.

Step-by-step explanation:

The empirical rule states that for a normal distribution, nearly all of the data will fall within three standard deviations of the mean . The empirical rule is further illustrated below

68% of data falls within the first standard deviation from the mean.

95% fall within two standard deviations.

99.7% fall within three standard deviations.

From the information given, the mean is 63 seconds and the standard deviation is 5 seconds.

2 standard deviations = 2 × 0.5 = 1

63 - 1 = 62 seconds

63 + 1 = 64 seconds

Therefore, in 95% of races, his finishing time will be between 62 and 64 seconds.

6 0
3 years ago
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