<span>Point B has coordinates (3,-4) and lies on the circle. Draw the perpendiculars from point B to the x-axis and y-axis. Denote the points of intersection with x-axis A and with y-axis C. Consider the right triangle ABO (O is the origin), by tha conditions data: AB=4 and AO=3, then by Pythagorean theorem:
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{Note, that BO is a radius of circle and it wasn't necessarily to use Pythagorean theorem to find BO}
<span>The sine of the angle BOA is</span>

Since point B is placed in the IV quadrant, the sine of the angle that is <span> drawn in a standard position with its terminal ray will be </span>
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Answer:
Sandy should have evaluated (-2)³ as -8
Step-by-step explanation:
(-2)³ (6 - 3) - 5(2 + 3) = -8 · 3 - 5 · 5 = - 24 - 25 = - 49
Because:
(-2) · (-2) · (-2) = 4 · (-2) = - 8
God with you!!!
Answer:
ok i am confused so yea im done
Step-by-step explanation:
Answer: UW= 9√3
Step-by-step explanation:
This right triangle is a 30-60-90 triangle. This is a special triangle. Since this is a special triangle, the hypotenuse is 2x.
The hypotenuse is 18. We can figure out the length of x.
2x=18
x=9
Since we got 9, you would think it is the answer, but it's not. The length across the 60° angle is x√3. Now that we know the length across from 60°, we can plug in x.
9√3
We can check our answer by using Pythagorean Theorem.
9²+(9√3)²=18²
81+243=18²
324=324
Since they are equal, we know we have the right answer.
Out of the 3 choices, I’d say it’s C.
180 degrees because 180 degrees means a straight line and it’s not close to 90, a right angle. It seems like a closer angle to a straight line.