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katovenus [111]
3 years ago
9

Convert to scientific notation. 1,860,000,000

Mathematics
1 answer:
dolphi86 [110]3 years ago
3 0
<span>1.86 x 10^9 </span>
1.86E+9
(Scientific E-notation)
<span>
</span>
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IceJOKER [234]
That is how I solved that :)

8 0
3 years ago
Put the steps in order to show how to solve the equation 4y - 7 = 25
kumpel [21]

Answer:  E, A, D, C, B

Step-by-step explanation:

First, we need to get y alone. So we will add 7 to the side of the equation that has the 4y in it.

So the first one will be.

<em><u>Add 7 to both sides of the equation.</u></em>

Now the second one is

<em><u>4y = 25 + 7  </u></em>Because what you do to one side of the equation, you do to the other. So we add 7 to 25.

Then the 3rd one will be <u><em>4y = 32  </em></u>because 25+7 is equal to 32. But we still have that 4y on the other side of the equation. So the next equation is 4y = 32.

The second to last step is <em><u>Divide both sides by 4  </u></em>because thats

how you isolate y. So once you divide both sides by 4. You will get 8. Leading you into the next and final step.

<em><u>Y = 8</u></em>

And thats how you do it!

8 0
3 years ago
Question in photo—————————-
IgorC [24]

Answer:

Answer is -8.........bro

8 0
3 years ago
Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!
Kitty [74]

Answer & Step-by-step explanation:

In the problem, we are given an equation. h(t) = -20 + 11t

In the equation, t represents an unknown value. So, if we are given a number that is in the replacement of t, then we can plug that number in to where t is at.

t = 11

h(11) = -20 + 11(11)

h(11) = -20 + 121

h(11) = 101

So, h(11) is equal to 101

3 0
3 years ago
Read 2 more answers
The total interest paid on a 3​-year loan at 9​% interest compounded monthly is ​$1505.82 determine the monthly payment for the
Kruka [31]
Number of compounding periods is
n=12months×3years=36
I assume that

The total interest=
monthly payment×number of compounding periods - the amount of the present value of an annuity ordinary
I=x×n-pv

Let monthly payment be X

I =Total interest is 1505.82

The present value of an annuity ordinary is
Pv=X [(1-(1+0.09/12)^(-36))÷(0.09/12)]

now plug those in the formula of the total interest above
I=x×n-pv
1505.72=36X-X [(1-(1+0.09/12)^(-36))÷(0.09/12)]
Solve for X using Google calculator to get the monthly payment which is
X=330.72

Check your answer using the interest formula
36×330.72−330.72×((1−(1+0.09
÷12)^(−12×3))÷(0.09÷12))
=1,505.83



3 0
3 years ago
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