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yuradex [85]
3 years ago
15

Infinite Algebra 2

Mathematics
1 answer:
Irina-Kira [14]3 years ago
4 0
The first problem, all you need to do is combine like terms then isolate the n:
4n-2n=4
~subtract 2n from 4n (2n)
2n=4
~then divide both sides of the equation by 2 to isolate the n
n=4

The second problem follows the same steps of combining like terms and isolating the variable. Here, you'll have to combine 2 like terms:
-12=2+5v+2v
~first combine the variables which is just 5v+2v which is 7v
-12=2+7v
~then subtract 2 from both sides to isolate the 7v
-14=7v
~then divide both sides by 7 to isolate the v and get your answer
-2=v

Hope that helped!
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[15 ÷ 5 • 3 + (2³ – 3)] + [4 • (36 – 3³)]
liubo4ka [24]

Answer:

50

Step-by-step explanation:

[15 ÷ 5 • 3 + (2³ – 3)] + [4 • (36 – 3³)]

[3 × 3 + (8 - 3)] + [4 × (36 - 27)]

(9 + 5) + (4 × 9)

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3 years ago
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Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

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c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
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---------------add

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