Answer:
Number of year to get $10,000 as interest = 7.5 year (Approx)
Step-by-step explanation:
Given:
Initial investment = $20,000
Interest on investment = $10,000
Rate of interest = 5.6% = 0.056
Find:
Number of year to get $10,000 as interest:
Computation:
![Interest\ on\ investment = Initial\ investment[(1+r)^n-1]\\\\10,000 = 20,000[(1+0.056)-1]\\\\0.5=(1.056)^n-1\\\\1.5 =(1.056)^n\\\\n=7.44](https://tex.z-dn.net/?f=Interest%5C%20on%5C%20investment%20%3D%20Initial%5C%20investment%5B%281%2Br%29%5En-1%5D%5C%5C%5C%5C10%2C000%20%3D%2020%2C000%5B%281%2B0.056%29-1%5D%5C%5C%5C%5C0.5%3D%281.056%29%5En-1%5C%5C%5C%5C1.5%20%3D%281.056%29%5En%5C%5C%5C%5Cn%3D7.44)
Number of year to get $10,000 as interest = 7.44
Number of year to get $10,000 as interest = 7.5 year (Approx)
In the equation of a circle in the form (x-h)^2 + (y-k)^2 = r^2, (h,k) is the center and r is the radius.
So, the center of the circle is at (-4,2) with radius 6 units.
Answer:$11.5
Step-by-step explanation:
Admission = $9 charged once
each ride = $2.5x (x=number of rides)
Total cost for x rides
=2.5x+9
This one.
The doubly-shaded area is the solution set. The dashed line is not included.
As i can see there is a table a bove so the x is the first number which going up the graph and the y is across the line
