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3 years ago

Write the expression in complete factored form. X2+6x-xy-6y

Mathematics

2 answers:

Liono4ka [1.6K]3 years ago

7 0

Answer:

(x-y) (x+6) or (x-6) (x+y)

Step-by-step explanation:

weqwewe [10]3 years ago

6 0

Answer:

(x-y)(x+6)

Step-by-step explanation:

x^2+6x-xy-6y

x*(x+6)-y(x+6)

(x-y)(x+6)

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Which algebraic expressions are polynomials? Check all that apply.

olganol [36]

the options that are polynomials are:

3.9x³-4.1x² + 7.3

x²y²-4x³+12y

4-x²

<h3>Which algebraic expressions are polynomials?</h3>

A polynomial is an expression of the form:

p(x) = aₙ*xⁿ + ...+ a₂*x² + a₁*x + a₀

Where all the exponents of the variable are whole numbers, and in this case we have only one variable x, but we could have any number of variables.

With that in mind, the options that are polynomials are:

3.9x³-4.1x² + 7.3

x²y²-4x³+12y

4-x²

These 3 expressions are polynomials.

If you want to learn more about polynomials:

brainly.com/question/4142886

#SPJ1

6 0

2 years ago

I need to put 3y+18=-8x+3 In slope intercept form

Elza [17]

Subtract 18 from each side to move the b to the right side. Now you can divide each side by 3 to get y by it self.

5 0

3 years ago

Which of these strategies would eliminate a variable in the system of equations? \begin{cases} 6x + 5y = 1 \\\\ 6x - 5y = 7 \end

frez [133]

Answer:

Option A and B are correct

Step-by-step explanation:

We have to add here

6x+5y=1.

6x-5y=7

sow e will get 12x=8 , x=8/12=2/3

Option A is correct.

If We substract bottom from furst then

6x+5y=1

-6x+5y=-7

10y=-6

y=-6/10=-3/5

we put y=-3/5 in any equation and find x

6x+5(-3/5)=1

6x=4

x=4/6=2/3

So Option B also correct.

5 0

3 years ago

Help me out please?<br>chapter : exponents and powers

belka [17]

Answer:

$\frac{125}{27}$

Step-by-step explanation:

$\frac{2^{-4} \times 15^{-3} \times 625}{5^2 \times 10^{-4}}$

Lets expand all the composite numbers into prime numbers.

$=> \frac{2^{-4} \times (3^{-3} \times 5^{-3}) \times 5^4}{5^2 \times (2^{-4} \times 5^{-4})}$

Lets cancel $2^{-4}$ from numerator and denominator.

$=> \frac{3^{-3} \times 5^{-3} \times 5^4}{5^2 \times 5^{-4}}$

Using laws of exponents , lets solve this.

$=> \frac{3^{-3} \times 5^{(-3 + 4)}}{5^{( 2 - 4)}}$

$=> \frac{3^{-3} \times 5^{1}}{5^{-2}}$

$=> 3^{-3} \times 5^{[1 - (-2)]}$

$=> 3^{-3} \times 5^{3}$

$=> \frac{5^3}{3^3} = \frac{125}{27}$

4 0

3 years ago

Read 2 more answers

What is 3,072/3 Explain in steps,Answer quick

Paha777 [63]

1024 is the answer to this problem.

7 0

3 years ago