<img src="https://tex.z-dn.net/?f=5x%20%2B%201%20%5Cleqslant%204" id="TexFormula1" title="5x + 1 \leqslant 4" alt="5x + 1 \leqsl

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natita [175]

3 years ago

ant 4" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Oduvanchick [21]3 years ago

8 0

the answer is x≤3/5 girl just go on cymath

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The population of a town was 25,000 people. then, 3,200 people moved away.. what was the percent decrease?

bogdanovich [222]

It Is B.21.8%, Simple way to figure this out is round B to 20%, If 3200 equals 20% and 20% times 5 equals 100% all you do is multiply 3200 by 5.

3 0

3 years ago

Read 2 more answers

What is the side length of the eectagkes

dedylja [7]

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Step-by-step explanation:

1. 5 in and 1/3 in

Here,

$Let\\l=5\\w=\frac{1}{3}\\Area=l*w\\=5*\frac{1}{3}\\=\frac{5}{3}\ in^2$

2. 5 in and 4/3 in

Here,

$l= 5\ in\\w=\frac{4}{3}\ in\\Area=l*w\\=5*\frac{4}{3}\\=\frac{20}{3}\ in^2$

3. 5/2 in and 4/3 in

$let\\l=\frac{5}{2}\\w=\frac{4}{3}\\Area= \frac{5}{2}*\frac{4}{3}\\=\frac{20}{6}=\frac{10}{3}\ in^2$

4. 7/6 in and 6/7 in

Let

$l=\frac{6}{7}\\w=\frac{7}{6}\\Area=l*w\\=\frac{6}{7}*\frac{7}{6}\\=1\ in^2$

Hence,

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Keywords: Rectangle, Area

Learn more about rectangles at:

#LearnwithBrainly

8 0

3 years ago

A company uses three different assembly lines- A1, A2, and A3- to manufacture a particular component. Of thosemanufactured by li

hammer [34]

Answer:

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

Denote R as the event that a component needs rework.

It is given that:

$P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20$

Compute the probability that a randomly selected component needs rework as follows:

$P(R)=P(R|A_{1})P(A_{1})+P(R|A_{2})P(A_{2})+P(R|A_{3})P(A_{3})\\=(0.05\times0.50)+(0.08\times0.30)+(0.10\times0.20)\\=0.069$

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

$P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069} =0.3623$

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

6 0

3 years ago

Jillian is trying to save water, so she reduces the size of her square grass lawn by 8 feet on each side the area of the smaller

horsena [70]

Answer: 20 feet by 20 feet.

Step-by-step explanation:

1. You know that $x$ is the original measure of one side. Since it is a square, all its sides are equal.

2. Therefore, to solve the problem you only need to solve for $x$ , as you can see below:

- You have that:

$(a-b)^{2}=a^{2}-2ab+b^{2}$

- Then, you obtain the following quadratic equation:

$(x-8)^{2} =144\\x^{2}-2(x)(8)+8^{2}=144\\x^{2}-16x-80=0$

- Apply the Quadratic formula to solve it:

$x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}\\a=1\\b=-16\\c=-80$

- Then, you obtain:

$x_1=20\\x_2=-4$

3. The dimensions cannot be negative, therefore, the answer is: 20 feet by 20 feet.

3 0

3 years ago

Read 2 more answers

What's 76 divided by 9 equals something or 9 / 76 equals something what's the answer easy one

zzz [600]

The answer is 76 divided by 9 equals 8.44

4 0

2 years ago